Answer:
The probability that at least 280 of these students are smokers is 0.9664.
Step-by-step explanation:
Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers
The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.
But the sample selected is too large and the probability of success is close to 0.50.
So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:
1. np ≥ 10
2. n(1 - p) ≥ 10
Check the conditions as follows:

Thus, a Normal approximation to binomial can be applied.
So,

Compute the probability that at least 280 of these students are smokers as follows:
Apply continuity correction:
P (X ≥ 280) = P (X > 280 + 0.50)
= P (X > 280.50)

*Use a <em>z</em>-table for the probability.
Thus, the probability that at least 280 of these students are smokers is 0.9664.
ANSWER
![3 {x}^{2} y \sqrt[4]{y}](https://tex.z-dn.net/?f=3%20%7Bx%7D%5E%7B2%7D%20y%20%5Csqrt%5B4%5D%7By%7D%20)
EXPLANATION
We want to simplify:
![\sqrt[4]{81 {x}^{8} {y}^{5} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B81%20%7Bx%7D%5E%7B8%7D%20%7By%7D%5E%7B5%7D%20%20%7D%20)
We can split the radical sign to obtain:
![\sqrt[4]{81} \times \sqrt[4]{ {x}^{8} } \times \sqrt[4]{ {y}^{5} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B81%7D%20%20%5Ctimes%20%20%5Csqrt%5B4%5D%7B%20%7Bx%7D%5E%7B8%7D%20%7D%20%20%5Ctimes%20%20%5Csqrt%5B4%5D%7B%20%7By%7D%5E%7B5%7D%20%7D%20)
Or
![\sqrt[4]{81} \times \sqrt[4]{ {x}^{8} } \times \sqrt[4]{ {y}^{4} \times y}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B81%7D%20%20%5Ctimes%20%20%5Csqrt%5B4%5D%7B%20%7Bx%7D%5E%7B8%7D%20%7D%20%20%5Ctimes%20%20%5Csqrt%5B4%5D%7B%20%7By%7D%5E%7B4%7D%20%20%5Ctimes%20y%7D%20)
![\sqrt[4]{81} \times \sqrt[4]{ {x}^{8} } \times \sqrt[4]{ {y}^{4}} \times \sqrt[4]{y}](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B81%7D%20%20%5Ctimes%20%20%5Csqrt%5B4%5D%7B%20%7Bx%7D%5E%7B8%7D%20%7D%20%20%5Ctimes%20%20%5Csqrt%5B4%5D%7B%20%7By%7D%5E%7B4%7D%7D%20%20%5Ctimes%20%20%5Csqrt%5B4%5D%7By%7D%20)
![\sqrt[4]{ {3}^{4} } \times \sqrt[4]{ {x}^{8} } \times \sqrt[4]{ {y}^{4}} \times \sqrt[4]{y}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%20%7B3%7D%5E%7B4%7D%20%7D%20%20%5Ctimes%20%20%5Csqrt%5B4%5D%7B%20%7Bx%7D%5E%7B8%7D%20%7D%20%20%5Ctimes%20%20%5Csqrt%5B4%5D%7B%20%7By%7D%5E%7B4%7D%7D%20%20%5Ctimes%20%20%5Csqrt%5B4%5D%7By%7D%20)
Recall that:
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![{3}^{4 \times \frac{1}{4} } \times {x}^{8 \times \frac{1}{4} } \times {y}^{4 \times \frac{1}{4} }\times \sqrt[4]{y}](https://tex.z-dn.net/?f=%7B3%7D%5E%7B4%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B4%7D%20%7D%20%20%5Ctimes%20%20%7Bx%7D%5E%7B8%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B4%7D%20%20%7D%20%20%5Ctimes%20%20%7By%7D%5E%7B4%20%5Ctimes%20%20%5Cfrac%7B1%7D%7B4%7D%20%7D%5Ctimes%20%20%5Csqrt%5B4%5D%7By%7D%20)
![3 {x}^{2} y \sqrt[4]{y}](https://tex.z-dn.net/?f=3%20%7Bx%7D%5E%7B2%7D%20y%20%5Csqrt%5B4%5D%7By%7D%20)
Answer:
No, Barbra is wrong as cost of 1 loaf of bread is £1.50 not $1.40.
Step-by-step explanation:
Note: This question is not complete. The complete question is therefore provided before answering the question as follows:
Barbara buys 3 boxes of eggs costing £1.20 each
1 jar of mayo costing £1.80
2 loaves of bread
she pays £10 note and gets £1.60 change
Barbara works out the cost of 1 loaf of bread as £1.40.
Is she correct? You MUST show your working out.
The explanation of the answer is now given as follows:
Total cost of 3 boxes of eggs = Number of boxes of eggs bought * Price per box of egg = 3 * £1.2 = £3.60
Cost of 1 jar of mayo = £1.80
Total amount spent = Note paid - Change collected = £10 - £1.60 = £8.40
Total cost of 2 loaves of bread = Total amount spent - Total cost of 3 boxes of eggs - Cost of 1 jar of mayo = £8.40 - £3.60 - £1.80 = £3.00
Cost of 1 loaf of bread = Total cost of 2 loaves of bread / 2 = £3.00 / 2 = £1.50
Therefore, Barbra is wrong as cost of 1 loaf of bread is £1.50 not $1.40.
Answer:
-4 and 8
Step-by-step explanation:
When looking at the number line to get the opposite of a number take your number and count that many numbers on the opposite side of the 0 (zero).
So if your number is -4 count that many on the opposite side of the zero to get 4.
Answer:
i think c but im not positive
Step-by-step explanation: