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fomenos
3 years ago
15

(01.05) What is the equation, in slope-intercept form, of the line that passes through (0, −2) and has a slope of −3? (5 points)

Select one:
Mathematics
1 answer:
nikklg [1K]3 years ago
4 0
I really don’t know im sorry
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HURRY THIS IS TIMED. I WILL GIVE BRANIEST IF CORRECT. EXPLAIN YOUR ANSWER!! THX
Aleks [24]

Answer: A and c

Step-by-step explanation: because they are the only ones that have p,x,m and not just seperate.

4 0
3 years ago
Read 2 more answers
If for every 12 blue streamers there is 9 gold streamers, how many blue streamers will I have if I have 36 gold streamers?
neonofarm [45]

Answer:

You will have 48 blue streamers.

Step-by-step explanation:

This question can be solved by proportions, using rule of three.

We have that:

For 12 blue streamers, there are have 9 gold streamers. How many blue streamers are there when there are 36 gold streamers?

12 blue - 9 gold

x blue - 36 gold

Applying cross multiplication

9x = 36*12

Simplifying by 9

x = 4*12 = 48

You will have 48 blue streamers.

4 0
3 years ago
please solve this question
____ [38]
A, c, and e are the correct answers
3 0
3 years ago
Read 2 more answers
D(x)=(x^2-12x+20)/(3x)
krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



6 0
3 years ago
How do I solve the equation?
trapecia [35]

Answer:

(-3, 5) radius- r= 5

Step-by-step explanation:

x^2+6x+y^2-10y=-9

Rewrite ^2+6x+y^2-10y=-9 in the form of the standard circle equation

(x-(-3))^2+(y-5)^2= 5^2

Therefore the circle properties are:

(a, b)=(-3, 5), r= 5

Download pdf
5 0
3 years ago
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