Well, we'll use the distributive property whenever x by itself is being added/subtracted to another number and a number is outside the parentheses :P.
3(x + 5) ------> 3 times x + 3 times 5 -----> 3x + 15.
2(x + 2) ------> 2 times x + 2 times 2 -----> 2x + 2
Now once you get all the variables on the left side of the equation and the positive numbers on the right side of the equation, x = 9. To check, just type this problem into an algebraic calculator and you'll get the same results! c:
