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3 years ago

Solve for x. 3(x + 5) - 2(x + 2) = 20

2 answers:

7 0

Well, we'll use the distributive property whenever x by itself is being added/subtracted to another number and a number is outside the parentheses :P.

3(x + 5) ------> 3 times x + 3 times 5 -----> 3x + 15.

2(x + 2) ------> 2 times x + 2 times 2 -----> 2x + 2

Now once you get all the variables on the left side of the equation and the positive numbers on the right side of the equation, x = 9. To check, just type this problem into an algebraic calculator and you'll get the same results! c:

IRINA_888 [86]3 years ago

4 0

[tex] 3(x + 5) - 2(x + 2) = 20 \\
3x + 15 - 2x - 4 = 20\\
5x + 11 = 20\\
5x = 9\\
x = 1\frac{4}{5} [tex]

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Which shows how to find the value of this expression when x=-2 and y=5? <br> (3x^3y^-2)2

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Put x = -2 and y = 5 to the expression.

$(3x^3y^{-2})^2$

$\left[3\cdot(-2)^3(5)^{-2}\right]^2=\left[3(-8)\cdot\dfrac{1}{5^2}\right]^2=\left(-24\cdot\dfrac{1}{25}\right)^2=\left(-\dfrac{24}{25}\right)^2\\\\=\dfrac{24^2}{25^2}=\dfrac{576}{625}$

explanation

$(-2)^3=(-2)(-2)(-2)=-8\\\\a^{-n}=\dfrac{1}{a^n}\to5^{-2}=\dfrac{1}{5^2}=\dfrac{1}{(5)(5)}=\dfrac{1}{25}\\\\a^2\geq0\ \text{for any real number}\to\left(-\dfrac{24}{25}\right)^2=\left(\dfrac{24}{25}\right)^2\\\\\left(\dfrac{a}{b}\right)^2=\dfrac{a^2}{b^2}\to\left(\dfrac{24}{25}\right)^2=\dfrac{24^2}{25^2}=\dfrac{(24)(24)}{(25)(25)}=\dfrac{576}{625}$

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4 years ago

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(

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