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Anit [1.1K]
3 years ago
8

Which quantity could go in the blank to make the equation below true r+3r+_=6r

Mathematics
2 answers:
AveGali [126]3 years ago
5 0

Answer:

2r

Step-by-step explanation:

r+3r_=6r

The left side would have to equal 6r

right now it is 4r

by adding 2r it would equal 6r making the equation true.

Hope this helps :)

creativ13 [48]3 years ago
4 0

Answer:

2r

Step-by-step explanation:

r+3r+_=6r

Let's simplify this first.  Subtract (r + 3r), or 4r, from both sides, obtaining

0 + _ = 2r

Then the quantity 2r, when placed in the blank, makes the equation true.

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Step-by-step explanation:

Factor the following:

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Factor the quadratic 4 x^2 + 24 x + 27. The coefficient of x^2 is 4 and the constant term is 27. The product of 4 and 27 is 108. The factors of 108 which sum to 24 are 6 and 18. So 4 x^2 + 24 x + 27 = 4 x^2 + 18 x + 6 x + 27 = 9 (2 x + 3) + 2 x (2 x + 3):

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