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Bond [772]
3 years ago
14

PLEAAASE ANSWER TIMER IS RUNNING OUT

Mathematics
2 answers:
Digiron [165]3 years ago
7 0

Answer:

C    Mark me as brainliest!!!

Step-by-step explanation:

lisabon 2012 [21]3 years ago
4 0

Answer:

the correct answer is 1/2.

How i came to this answer was adding all of the number of medals together for all of the years, coming up to a total of 22. When asking about probability of any given set or amount of things, you always take the selected values and take them out of the whole amount. Years 2009 and 2012 have a whole selected value of 11 (4+7). Therefore you're "taking" 11 from 22, coming up with the fraction 11/22 seeing as that is not a answer choice the next step is to simply the fraction to 1/2.

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6,000 dollars is invested in two different accounts earning 3% and 5% interest. At the end of one year, the two accounts earned
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Answer:

$2000

Step-by-step explanation:

6,000 dollars is invested in two different accounts earning 3% and 5% interest.

Let x be the amount invested in account earning 3% interest

So, 6000-x is the amount invested in account earning 5% interest

S.I. =\frac{P\times R\times T}{100}

So, Simple interest for account earning 3% interest

S.I. =\frac{x \times 3 \times 1}{100}

S.I. =0.03x

Simple interest for account earning 5% interest

S.I. =\frac{(6000-x) \times 5 \times 1}{100}

S.I. =0.05(6000-x)

S.I. =300-0.05x

Since we are given that the two accounts earned $220 in interest

So, 0.03x+300-0.05x=220

−0.02x+300=220

80=0.02x

\frac{80}{0.02}=x

4000=x

So, 4000 was invested at 3%

(6000-x)=6000-4000=2000 was invested at 5%

Hence 2000 was invested at 5%

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