Answer:
Parameter
Step-by-step explanation:
Required
Parameter of Statistic
From the question, we understand that the teacher is to calculate the class average.
To calculate the class average, the teacher will use the mean function/formula, which is calculated as:

Generally, mean is an example of a parameter.
<em>So, we can conclude that the teacher will use parameer</em>
Answer:a gallon
Step-by-step explanation:if you add cup by cup you can see that it is a gallon by adding them or putting it in a allon jug
15-9= 6 the difference is 6 people. i hope this is what you were looking for.
Answer:
3
Step-by-step explanation:
63/21 = 3
Answer with Step-by-step explanation:
We are given that

Let g(x,y)=
We have to find the extreme values of the given function


Using Lagrange multipliers



Possible value x=0 or 
If x=0 then substitute the value in g(x,y)
Then, we get 


If
and substitute in the equation
Then , we get possible value of y=0
When y=0 substitute in g(x,y) then we get

Hence, function has possible extreme values at points (0,1),(0,-1), (1,0) and (-1,0).




Therefore, the maximum value of f on the circle
is
and minimum value of 