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mixas84 [53]
4 years ago
9

What integer is equivialnt to 25 3/2

Mathematics
1 answer:
Evgesh-ka [11]4 years ago
4 0

Answer: There is none.

Step-by-step explanation:

Fractions and decimals can't be integers.

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Use the laplace transform to solve the given initial-value problem. y' + y = (t − 1), y(0) = 3
GaryK [48]

In mathematics, the Laplace transform, named after its discoverer Pierre Simon Laplace, transforms a function of real variables (usually in the time domain) into a function of complex variables (in the time domain). is the integral transform that Complex frequency domain, also called S-area or S-plane).

Learn more about Laplace transform here brainly.com/question/17062586

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5 0
2 years ago
Whats 7.273 divided by 6
Alex_Xolod [135]

Step-by-step explanation:

The number 7273 is called the numerator or dividend, and the number 6 is called the denominator or divisor.

The quotient of 7273 and 6, the ratio of 7273 and 6, as well as the fraction of 7273 and 6 all mean (almost) the same:

7273 divided by 6, often written as 7273/6.

Read on to find the result of 7273 divided by 6 in decimal notation, along with its properties.

6 0
2 years ago
Read 2 more answers
Find a particular solution to y" - y' + 9y = 3 sin 3x
Dima020 [189]

Answer:

cos3x

Step-by-step explanation:

y" - y' + 9y = 3 sin 3x

D^{2}y-Dy+9y=3 sin3x

y=\frac{3 sin 3x}{(D^{2} -D+9}=3 sin 3x

here D^2 will be replaced by  \alpha^2 where \alpha is coefficient of x

y=\frac{3 sin 3x}{-3^{2} -D+9}

y=-3\frac{sin 3x}{D}

y=-3\int\ {sin 3x} \, dx

y=-3\frac{cos3x}{-3}

y=cos3x

hence Particular solution is cos3x

6 0
4 years ago
Could u help me please​
mezya [45]
X=26
62=2x+10 (minus 10 from both sides)
52=2x (divide 2 from both sides)
26=x
8 0
3 years ago
A rectangular field is 100 meters wide and 140meters long. Give the length and width of another rectangular field that has the s
sertanlavr [38]

Answer:

The length of rectangle 2  = 80 m

The width of rectangle 2  = 160 m

Step-by-step explanation:

The width of rectangle 1  = 100 m

The length of rectangle 1  = 140 m

Now the PERIMETER OF A RECTANGLE = 2 (L+B)

So, here the Perimeter of R 1 =  2 ( 100 + 140)  = 2 x 240  = 480 m

Also, AREA OF THE RECTANGLE = LENGTH x WIDTH

So, here the Area of R 1 =  100 x 140  = 14,000  sq m  

Now, in the Rectangle  2:

Let us assume the width of rectangle 2  = x

Assume the length of rectangle 2  = y  

Now,Perimeter of rectangle 2= Perimeter of rectangle 1

⇒ 2 (x + y)  = 480 m ......... (1)

Also, Area of rectangle 2   <  Area of rectangle 1

⇒ x y  < 14,000  .....  (2)

Now, solving both  the equations, we get

(x +y ) = 240  ⇒  y = 240 - x

x y < 14,000

Substituting y = 240 - x in (2), we get:

x (240-x) < 14,000

or, 0< x^2 -240x +14,000

Solving the above equation, we get

x < 140

Now, if we take x  = 80, then y = 160

So, for x = 80, y = 160,

Perimeter = 2 ( 80 + 160) = 240 m

Area = x y  = 80 x 160  = 12,800 < 14,000

Hence, one possible pair of solution for (x,y) =(80,160)

6 0
3 years ago
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