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Arturiano [62]
3 years ago
6

Could u help me please​

Mathematics
1 answer:
mezya [45]3 years ago
8 0
X=26
62=2x+10 (minus 10 from both sides)
52=2x (divide 2 from both sides)
26=x
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A = (5)<br> b = (3)<br> Work out 4a + b
malfutka [58]

Step-by-step explanation:

IF A=5, B=3

4*5+3=20+3

         =23

THE ANSWER IS 23

8 0
3 years ago
The cost of a pound of nails increased from ​$2.17 to ​$2.52. What is the percent of increase to the nearest​ whole-number perce
Cloud [144]

Answer:

16%  is the percent of increase to the nearest​ whole-number percent.

Step-by-step explanation:

As the cost of a pound of nails increased from ​$2.17 to ​$2.52.

  • $2.52 - $2.17 = $0.35

so dividing the 0.35 by 2.17 would give us the percetange of increase

  • 0.35/2.17 = 0.16 which is 16%.

Therefore, 16%  is the percent of increase to the nearest​ whole-number percent.

7 0
3 years ago
Justin used 3/4 of a gallon of paint on 3/4 of a wall. How many gallons does he need for one wall?
blondinia [14]

Answer:

Step-by-step explanation:

1/4

7 0
3 years ago
Read 2 more answers
Evaluate the expression a3 -b/c for a = 3, b = 2 and c = 4. write in simplest form
Scilla [17]
Hello There!

Write out your equation:
(a^3 - b)/c
Substitute the values in:
(3^3 - 2)/4
Simplify:
(27 - 2)/4
25/4
Solve:
It is 6.25.

Therefore, your answer is 6 1/4.

Hope This Helps You!
Good Luck :) 

- Hannah ❤

6 0
4 years ago
PLEASE PLEASE HELP! Find the measure of APB^.
Whitepunk [10]

Answer:

65°

Step-by-step explanation:

Radii CA and CB are perpendicular to tangent lines AT and BT, so

\angle CAT=\angle CBT=90^{\circ}

Since angle BAT is equal to 65°, angle CAB has measure

\angle CAB=90^{\circ}-65^{\circ}=25^{\circ}.

Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus

\angle CBA=\angle CAB=25^{\circ}

The sum of the measures of all interior angles in triangle is always 180°, so

\angle CAB+\angle CBA+\angle ACB=180^{\circ}\\ \\25^{\circ}+25^{\circ}+\angle ACB=180^{\circ}\\ \\\angle ACB=130^{\circ}

Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so

x=\angle APB=\dfrac{1}{2}\cdot 130^{\circ}=65^{\circ}

8 0
3 years ago
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