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krok68 [10]
3 years ago
11

A restaurant gives each child customer a fun pack. There are exactly 12 stickers in each fun pack. The restaurant has 615 sticke

rs.
What is the greatest number of fun packs that the restaurant can make?
Mathematics
1 answer:
Galina-37 [17]3 years ago
4 0

Answer:

51

Step-by-step explanation:

Let x represent fun packs

We know there are 12 stickers per fun pack, and they have 615 stickers, so an equation could be

12x=615

Divide both sides by 12 to isolate x

x=51.25

But, because they can't make 0.25 of a fun pack, the greatest number they can make is 51 fun packs

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Karo-lina-s [1.5K]

Answer:

Perimeter of the rectangle = 8 x +4

Length of the rectangle = 12 units.

Step-by-step explanation:

Let the width of the rectangle as 'x' units.

So, length of the rectangle is 2 more than 3 x.

We can set up expression for length as 3 x+2.

Now, perimeter is sum of all side lengths of the rectangle.

So, perimeter = x+x+3 x+2 +3 x+2

Combine like terms,

Perimeter = 8 x+4

Now, it is given perimeter is 36cm

So,

8 x+4=36

Subtract both sides 4

8 x=32

Divide both sides by 8

x=4

So, width of the rectangle =4

Length =3(4) +2=14

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3 years ago
The perimeter of the square park is 240m, then the side of the square park is _______.
Colt1911 [192]

Step-by-step explanation:

A square's perimeter consists of 4 equal sides.

Therefore side of square park = 240m/4 = 60m.

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3 years ago
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5 – 6x = 8x + 17 and simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B-6%7D%7B7%7D" id="TexFormula1" title="\frac{-6}{7}" al
NikAS [45]

Answer:

x = -6/7

Step-by-step explanation:

5 – 6x = 8x + 17

-5                 - 5           Subtract 5 from both sides

-6x = 8x + 12

-8x   - 8x                     Subtract 8x from both sides

-14x = 12                      Divide both sides by -14

x = -12/14                     Simplify

x = -6/7

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3 years ago
Use the quadratic formula to find the solutions to the equation x^2-3x+1=0
Gnom [1K]

Answer:

x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}

Step-by-step explanation:

Using:

x=\frac{-b+-\sqrt{b^{2}-4*a*c} }{2*a}

we will have two solutions.

x^2-3x+1=0

So, a=1   b=-3  c=1

x_{1}=\frac{+3+\sqrt{-3^{2}-4*1*1} }{2*1}\\\\x_{2}=\frac{+3-\sqrt{-3^{2}-4*1*1} }{2*1}

We have two solutions:

x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}

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The answer is 4 lol
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