Answer:
2.05 inches
Step-by-step explanation:
V = 4/3 x πr³
36=4πr³/3
36x3= 4πr³
108= 4πr³
108/4 = πr³
27= πr^3
27/π =r³
r=
![\sqrt[3]{27 \div \pi}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B27%20%5Cdiv%20%5Cpi%7D%20)
r= 2.048in
round off to 2.05in
<u>PROOF</u>
V = 4÷3 x πr³
V= 4/3 x π(2.05)³
V=4/3 x π8.6
V=4×π×8.6/3
V=108/3
V=36in³
Therefore: radius= <u>2.05 inches</u>
Subtract 39. That is my answer. I hoped I helped!
If t=5 then all you do is plug that into the function:
h(t)=175(1028)5
You would start by multiplying 1028 by 5 which leaves you with 5140, now plug that into the function.
h(t)=175(5140)
multiply 175 and 5140
h(t)=899500