Answer:
The distance covered is 113.75 m
Step-by-step explanation:
As per the question:
The initial velocity of the train, v = 20 m/s
The final velocity of the train, v' = 6 m/s
Uniform deceleration, a = 1.6
Or uniform acceleration, a = - 1.6
<em>Here, the body decelerates, i.e., slows down at a uniform rate thus we take acceleration with negative sign.</em>
Now, to find the distance covered, s:
Using the eqn of Kinemetics:




In dividing two equation with variables and exponent, First you must align or rearrange the equation and group them base on their variables but don't forget the sign of each variables. Second, proceed in dividing its quantity and then subtract its exponent to the other variables having the same. So by calculating it, the answer would be X or X^1
The value of x would be 7
Answer:
log2(M)+log3(N)
simplifies to:
simplified step by step
Step-by-step explanation:
0.30103m+0.477121n.
the answer is
0.39103m+0.477121n