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Mandarinka [93]
3 years ago
8

In a large accounting firm, the proportion of accountants with MBA degrees and at least five years of professional experience is

75% as large as the proportion of accountants with no MBA degree and less than five years of professional experience. Furthermore, 35% of the accountants in this firm have MBA degrees, and 45% have fewer than five years of professional experience. If one of the firm's accountants is selected at random, what is the probability that this accountant has an MBA degree or at least five years of professional experience, but not both
Mathematics
1 answer:
Rasek [7]3 years ago
3 0

Answer:

The probability that this accountant has an MBA degree or at least five years of professional experience, but not both is 0.3

Step-by-step explanation:

From the given study,

Let A be the event that the accountant has an MBA degree

Let B be the event that the accountant has at least 5 years of professional experience.

P(A) = 0.35

P(A)^C = 1 - P(A)

P(A)^C = 1 - 0.35

P(A)^C = 0.65

P(B)^C = 0.45

P(B) = 1 - P(B)^C

P(B) = 1 - 0.45

P(B) = 0.55

P(A ∩ B ) = 0.75 P(A^C \ \cap  \  B^C)

P(A ∩ B ) = 0.75 [ 1 - P(A ∪ B) ]  because  P(A^C \ \cap  \  B^C)  = P(A \cup B)^C

SO;

P(A ∩ B ) = 0.75 [ 1 - P(A) - P(B) + P(A ∩ B) ]

P(A ∩ B ) = 0.75 [ 1 - 0.35 - 0.55 + P(A ∩ B) ]

P(A ∩ B ) - 0.75  P(A ∩ B) = 0.75 [1 - 0.35 -0.55 ]

0.25  P(A ∩ B) = 0.075

P(A ∩ B) = \dfrac{0.075}{0.25}

P(A ∩ B) = 0.3

The probability that this accountant has an MBA degree or at least five years of professional experience, but not both is: P(A ∪ B ) - P(A ∩ B)

= P(A) + P(B) - 2P( A ∩ B)

= (0.35 + 0.55) - 2(0.3)

= 0.9 - 0.6

= 0.3

∴

The probability that this accountant has an MBA degree or at least five years of professional experience, but not both is 0.3

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weeeeeb [17]

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8 0
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dezoksy [38]

Answer:

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Step-by-step explanation:

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3 years ago
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3 0
3 years ago
Read 2 more answers
What is the value of n 9 x 23 +3 x39 - 28 = n
Flura [38]
Ok :) we should do according to order of operations
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction    (PEMDAS) 'it will be helpful for to remember '
 
anyways ;
9×23=207
3×39=117 
 (we did those things because we should multiple before add )
so now we will add and subtract= 207+117-28 =296
 
I HOPE IT WILL MAKE SENSE !!!!!!!



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