6478 10's. To be accurate; 6478.5
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 25235
For the alternative hypothesis,
µ > 25235
This is a right tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 100,
Degrees of freedom, df = n - 1 = 100 - 1 = 99
t = (x - µ)/(s/√n)
Where
x = sample mean = 27524
µ = population mean = 25235
s = samples standard deviation = 6000
t = (27524 - 25235)/(6000/√100) = 3.815
We would determine the p value using the t test calculator. It becomes
p = 0.000119
Since alpha, 0.05 > than the p value, 0.000119, then we would reject the null hypothesis. There is sufficient evidence to support the claim that student-loan debt is higher than $25,235 in her area.
300 because
You have to multiply 81 times 100 and then divide by 27
Answer:
To find the "nth" term of an arithmetic sequence, start with the first term, a(1). Add to that the product of "n-1" and "d" (the difference between any two consecutive terms). For example, take the arithmetic sequence 3, 9, 15, 21, 27.... a(1) = 3. d = 6 (because the difference between consecutive terms is always 6.
Step-by-step explanation:
