Y = x + 3
to test all of these, just use the visible x-coordinates on the grid and substitute them in the equation.
eg; y = (2) + 3 --> y = 5 . So the line would cross through (2,5)
Joe is correct because Moe could choose two pieces but had a nine piece variety where as Joe could only choose from 7 pieces of candy
Answer:
7)
. 8)
Step-by-step explanation:
7)
Here we have two different types of faces.Bottom face and side faces which are equivalent.
To calculate the area of a trinagle we have the formula of area to be
where a is the height of the triangle and b is the base of the triangle.
here let us first calculate the area of the bottom face,


now for the top faces which are similar, areas would be


Hence the total area is

8)
As we have seen in the above question area for a traingle would be
and for rectangle would be
where l and b are the lengths and breaths of the rectangle.
Area of traingles would be ,


Area of rectangles would be,


Hence the total area is

Let the given sides be "a" and "b" and the unknown side be "c". The Law of Cosines tells you
.. c^2 = a^2 +b^2 -2ab*cos(C)
.. c^2 = 2^2 +3^2 -2*2*3*cos(60°)
.. c^2 = 7
.. c = √7 ≈ 2.6458
The third side of the triangle is √7, about 2.6458.