Differentiate it
get f ' (x)=3x^2-4
put 3x^2-4=0
x=2/√3,-2/√3
so interval
x∈(-2/√3,2/√3)
Answer:
(1) 820
(2) 1920
Step-by-step explanation:
(1) solving 20 x 41, using associative property.
20 * 41 = (2 x 10) x 41 = 2 x (10 x 41)
= 20 x 41 = 2 x 410
= 820 = 820
(2) distribute 32 as 30 + 2 and solve.
60 x 32
= 60 x (30 + 2) = 60(30) + 60(2)
= 1800 + 120
= 1920
nonsense because, 6 ≠ 12
Step-by-step explanation:
(15 - 6) - 3 = 15 - (6 - 3)
you gotta to the parentheses first.
9 - 3 = 15 - 3
6 = 12
6 ≠ 12
Y = -x + 4.....so sub in -x + 4 in for y in the other equation
x + 2y = -8
x + 2(-x + 4) = -8
x - 2x + 8 = -8
x - 2x = -8 - 8
-x = -16
x = 16
y = -x + 4
y = -16 + 4
y = - 12
one solution (16,-12)
