Question

The circumference of a basketball for college women must be from 28.5 in. To 29.0 in. What absolute value inequality represents the circumference of the ball

Answer 1

The circumference must be within half the difference of the average of those two numbers:

... |c -28.75| ≤ 0.25 . . . . where c is the circumference in inches

Answer 2

Answer:

$|C-28.75|\leq 0.5$

Step-by-step explanation:

Let C represent circumference of the ball.

We have been given that circumference of a basketball for college women must be from 28.5 in. to 29.0 in. We are asked to write an absolute value inequality for the given scenario.

$|\text{Actual}-\text{Ideal}|\leq \text{Tolerance}$

$\text{Tolerance}=29.0-28.5=0.5$

Ideal will be average of both circumference.

$\text{Ideal}=\frac{29.0+28.5}{2}$

$\text{Ideal}=\frac{57.5}{2}$

$\text{Ideal}=28.75$

Upon substituting our given values, we will get:

$|C-28.75|\leq 0.5$

Therefore, our required absolute value inequality would be $|C-28.75|\leq 0.5$.