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3 years ago

Solve each equation for the specified variable y+v=w solve for v

Mathematics

2 answers:

mylen [45]3 years ago

5 0

Answer:

v = w - y

Step-by-step explanation:

y + v = w

To solve for v. We subtract y on both sides.

y + v - y = w - y

v = w - y

nasty-shy [4]3 years ago

4 0

Answer: v=w-y

Step-by-step explanation:

y+v=w

-y -y

v=w-y

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A wheel for Lisa's bike has a diameter of 24 inches. What is the circumference, C, in inches? Use 3.14 for π

julsineya [31]

Answer:

75.36 inches

Step-by-step explanation:

C = π·d

C = 3.14(24)

C = 75.36

3 0

3 years ago

Graph the line x=-3

Nuetrik [128]

I think you would put an x on the -3 on a number line idk but yeahhh

7 0

3 years ago

Read 2 more answers

Find the distance between the given points: (2, -2) and (-4, 7)

sasho [114]

Answer:

$3\sqrt{13}$

Step-by-step explanation:

Hi there!

We want to find the distance between the points (2, -2) and (-4, 7).

To do that, we can use the distance formula.

The distance formula is given as $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ , where $(x_1, y_1)$ and $(x_2, y_2)$ are points

We have everything needed to find the distance, but let's label the values of the points to avoid any confusion

$x_1=2\\y_1=-2\\x_2=-4\\y_2=7$

Now substitute those values into the formula and solve

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$\sqrt{(-4-2)^2+(7--2)^2}$

Simplify

$\sqrt{(-4-2)^2+(7+2)^2}$

$\sqrt{(-6)^2+(9)^2}$

Square the numbers under the radical

$\sqrt{36+81}$

Add the numbers under the radical together

$\sqrt{117}$

Simplify the square root

$3\sqrt{13}$

Hope this helps!

6 0

3 years ago

Tell me please I need help with this one guys pleaseee thanks you so much :()))

siniylev [52]

A. At the very end
B.one more away from that
C.on the left

7 0

3 years ago

If g(x) = 3^(2x) then g'(2) is? A. 81 B. 162ln3 C. 81/ln3 D. 6/ln3 E. 6lin3

Alina [70]

$\bf a^{u(x)}\qquad \qquad \cfrac{df}{dx}=\cfrac{df}{du}\cdot \cfrac{du}{dx}\\\\
-----------------------------\\\\
g(x)=3^{2x}\qquad \qquad u=2x
\\\\\\
\cfrac{dg}{dx}=3^uln(3)\cdot \cfrac{du}{dx}\implies \cfrac{dg}{dx}=3^{2x}ln(3)\cdot 2
\\\\\\
g'(2)=3^{2\cdot 2}ln(3)\cdot 2\implies g'(2)=2\cdot 81ln(3)\implies g'(2)=162ln(3)$

5 0

3 years ago