K-3>4 can you get it

Select equivalent or not equivalent for each pair of expressions

marissa [1.9K]

Answer:

1: equivalent

2: equivalent

3: not equivalent

Step-by-step explanation:

for 1 & 2, you just switch the terms, but for 3, the 6z is not negative in the first expression, but it is in the second.

3 0

3 years ago

The blueprint of a rectangular fountain shows that the length will be 7 feet longer than twice it's width. The area of the recta

bazaltina [42]

Answer:

D .(w)(2w+7)=85

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Area of a rectangle: width x length

Since the length will be 7 feet longer than twice its width (w).

So, to obtain the length we have to multiply the width by 2 (twice) and add 7.

Mathematically speaking:

Length: 2w+7

Back with the area formula:

Area of a rectangle: length x width

Replacing with the values given:

85 = w (2w+7)

Note: option D correct equation is D .(w)(2w+7)=85, since we don't have x variables.

5 0

4 years ago

Find the z-score boundaries that separate a normal distribution as described in each of the following. a. The middle 20% from th

Anna007 [38]

Answer:

a) The boundaries are $Z = \pm 0.253$

b) The boundaries are $Z = \pm 0.675$ .

c) The boundaries are $Z = \pm 1.96$ .

d) The boundaries are $Z = \pm 2.575$ .

Step-by-step explanation:

Z-score:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

a. The middle 20% from the 80% in the tails.

The middle 20% is between the 50 - (20/2) = 40th percentile and the 50 + (20/2) = 60th percentile:

40th percentile: Z has a pvalue of 0.4, so Z = -0.253.

60th percentile: Z has a pvalue of 0.6, so Z = 0.253.

The boundaries are $Z = \pm 0.253$ .

b. The middle 50% from the 50% in the tails.

The middle 50% is between the 50 - (50/2) = 25th percentile and the 50 + (50/2) = 75th percentile:

25th percentile: Z has a pvalue of 0.25, so Z = -0.675.

75th percentile: Z has a pvalue of 0.75, so Z = 0.675.

The boundaries are $Z = \pm 0.675$ .

c. The middle 95% from the 5% in the tails.

The middle 95% is between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile:

2.5th percentile: Z has a pvalue of 0.025, so Z = -1.96.

97.5th percentile: Z has a pvalue of 0.975, so Z = 1.96.

The boundaries are $Z = \pm 1.96$ .

d. The middle 99% from the 1% in the tails.

The middle 99% is between the 50 - (99/2) = 0.5th percentile and the 50 + (99/2) = 99.5th percentile:

0.5th percentile: Z has a pvalue of 0.005, so Z = -2.575.

99.5th percentile: Z has a pvalue of 0.995, so Z = 2.575.

The boundaries are $Z = \pm 2.575$ .

6 0

3 years ago

What are the roots to<br> the equation<br> 2x² + 6x-1=0?

lys-0071 [83]

Answer:

The roots of equations are as m = $\frac{-3}{2} + \frac{\sqrt{11} }{2}$ And n = $\frac{-3}{2} - \frac{\sqrt{11} }{2}$

Step-by-step explanation:

The given quadratic equation is 2 x² + 6 x - 1 = 0

This equation is in form of a x² + b x + c = 0

Let the roots of the equation are ( m , n )

Now , sum of roots = $\frac{ - b}{a}$

And products of roots = $\frac{c}{a}$

So, m + n = $\frac{ - 6}{2}$ = - 3

And m × n = $\frac{ - 1}{2}$

Or, (m - n)² = (m + n)² - 4mn

Or, (m - n)² = (-3)² - 4 ( $\frac{ - 1}{2}$ )

Or, (m - n)² = 9 + 2 = 11

I.e m - n = $\sqrt{11}$

Again m + n = - 3 And m - n = $\sqrt{11}$

Solving this two equation

(m + n) + ( m - n) = - 3 + $\sqrt{11}$

I.e 2 m = - 3 + $\sqrt{11}$

Or, m = $\frac{-3}{2} + \frac{\sqrt{11} }{2}$

Similarly n = $\frac{-3}{2} - \frac{\sqrt{11} }{2}$

Hence the roots of equations are as m = $\frac{-3}{2} + \frac{\sqrt{11} }{2}$ And n = $\frac{-3}{2} - \frac{\sqrt{11} }{2}$ Answer

6 0

4 years ago

Determine the equivalent system for the given system of equations. 4x − 5y = 2 3x − y = 8

mel-nik [20]

Answer:

<h2>Explanation:</h2>

We have the following System of Linear Equations in two variables:

$\left \{ {4x-5y=2 \atop {3x-y=8}}\right.$

So let's call this as SYSTEM A. Two systems of equations are said to be equivalen if and only if they have the same solution, so we can get an equivalent system, called SYSTEM B, by multiplying an equation by some constant value. Let's say we multiply equation (1) by 2, then:

$\left \{ {2(4x-5y=2) \atop {3x-y=8}}\right. \\ \\ \left \{ {8x-10y=4 \atop {3x-y=8}}\right.$

In conclusion:

SYSTEM A:

$\left \{ {4x-5y=2 \atop {3x-y=8}}\right.$

SYSTEM B:

$\left \{ {8x-10y=4 \atop {3x-y=8}}\right.$

SYSTEM A and SYSTEM B are equivalent

<h2>Learn more:</h2>

System of equations: brainly.com/question/13799715

#LearnWithBrainly

5 0

3 years ago