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irina [24]
2 years ago
9

These are the four terms of the sequence 29,32,35,38. the question is write down the next term​

Mathematics
1 answer:
Andreas93 [3]2 years ago
4 0
The next term after 38 would be 41. You are just adding 3 to each number
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4) y=-4x-1<br> Finding slope
Lisa [10]

Answer:

4/1

Step-by-step explanation:

this is because it is 4x

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3 years ago
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A rectangular box has length 20cm, width 6cm and height 4cm. find how many cubes of size 2cm that will fit into the box.​
Papessa [141]

<u>Answer:</u>

\boxed{\pink{\sf The \ number \ of \ cubes \ that \ can \ be \ fitted \ is 60 .}}

<u>Step-by-step explanation:</u>

Given dimensions of the box = 20cm × 6cm × 4cm .

Dimension of the cube = 2cm × 2cm × 2cm .

Therefore the number of cubes that can be fitted into the box will be equal to the Volume of box divided by the Volume of the cube. So ,

\boxed{\red{\bf \implies No. \ of \ cubes \ = \dfrac{Volume \ of \ box}{Volume \ of \ cube }}}

\bf \implies n_{cubes} = \dfrac{20cm \times  6cm \times 4cm .}{2cm  \times 2cm  \times 2cm } \\\\\bf\implies n_{cubes}  = 10 \ times 3cm \times 2cm \\\\\implies \boxed{\bf n_{cubes}= 60 }

<h3><u>Hence</u><u> the</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>cubes</u><u> </u><u>that</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>fitted</u><u> </u><u>in</u><u> the</u><u> </u><u>box </u><u>is</u><u> </u><u>6</u><u>0</u><u> </u><u>.</u></h3>

6 0
3 years ago
How to find the area of a rectangular prism?
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8 0
3 years ago
What’s is the solution to the equation x to the power of 2 =16/25
skelet666 [1.2K]

Answer:

x=\dfrac{4}{5}

Step-by-step explanation:

The given equation is :

x^2=\dfrac{16}{25}

We need to find the value of x.

When the exponent 2 removes from LHS, it will shift to RHS as square root as follows :

x=\sqrt{\dfrac{16}{25}}

We know that, 4×4= 16 and 5×5 = 25

So,

x=\sqrt{\dfrac{4\times 4}{5\times 5}}\\\\x=\dfrac{4}{5}

So, the solution of the given equation is 4/5.

4 0
2 years ago
Help with this question
wlad13 [49]
<h3>A.</h3>

See below for a graph

<h3>B.</h3>

The inverse of a function appears on a graph as the reflection of the function across the line y=x. This is because the inverse relation is effectively the same relation with the variables x and y swapped. Here, the graphs of f(x) and g(x) are mirror images of each other across the line y=x, so we can see they are inverse functions.

The same technology allows us to graph y=f(g(x)) and y=g(f(x)). Both are graphs of y=x, as expected.

7 0
3 years ago
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