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Llana [10]
4 years ago
12

Find the 10th term in the following arithmetic sequence if the constant being added is

Mathematics
2 answers:
Nookie1986 [14]4 years ago
5 0

Answer:

10th term = -88.

Step-by-step explanation:

This is an arithmetic sequence with first term = 20 and common difference -12.

nth term = a1 + (n - 1)d

10th term  = 20 + (10-1)*-12

= 20 - 108

= -88.


Murljashka [212]4 years ago
3 0

Find the 10th term in the following arithmetic sequence if the constant being added is  -12

Step-by-step explanation:

20 - 12 = 8

8 - 12 = -4

-4 - 12 = -16

So the sequence will be

20; 8; -4; -16

an = 20 - 12(n - 1)

a10 = 20 - 12(10 - 1) = -88

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An algebra tile configuration shows only the product spot, which has 9 tiles in 3 columns with 3 rows. First row: 2 + x squared, 1 + x. Second row: 2 + x squared, 1 + x. Third row: 2 negative x, 1 negative.

The correct option is B.

Given

Equation; \rm 4x^2 - 1

<h3>Quadratic equation</h3>

It is a polynomial that is equal to zero.

Polynomial of variable power 2, 1, and 0 terms are there.

Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation.

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An algebra tile configuration showing only the product spot, which has 9 tiles in 3 columns with 3 rows. First row: 2 + x squared, 1 + x. Second row: 2 + x squared, 1 + x. Third row: 2 negative x, 1 negative.

Then,

The factors of the polynomial is;

\rm 4x^2 - 1=0\\\\ 4x^2-2x+2x-1=0\\\\ 2x(2x-1)+1(2x-1)=0\\\\(2x-1)(2x+1)=0

Hence, an algebra tile configuration shows only the product spot, which has 9 tiles in 3 columns with 3 rows. First row: 2 + x squared, 1 + x. Second row: 2 + x squared, 1 + x. Third row: 2 negative x, 1 negative.

More about the quadratic equation link is given below.

brainly.com/question/2263981

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3 years ago
Can someone please explain this to me I’m so confused and I have a quiz on this tomorrow
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We must solve for x by taking the square root of both sides.
But imagine x^2 = 9. x = 3 is a solution because 3^2 = 9. But x = -3 is also a solution because (-3)^2 = 9. So we need to add the plus and minus sign to account for all of our solutions.
                     √x^2 = √(16/100)
We square root both sides to remove the exponent 2 on x. Then
                         x = ±√(16/100)
Then we have to use a Property of Radicals which is √(x/y) = √(x) / √(y).
Then the square root of 16 is 4 and the square root of 100 is 10. 4/10 is 2/5 simplified.
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