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Kaylis [27]
3 years ago
14

show that if k is a positive constant, then the area between the x-axis and one arch of the curve y=sin kx is 2/k

Mathematics
1 answer:
Levart [38]3 years ago
8 0
Sin(kx)=0=>x=0,π,...
∫0πsin(kx)dx=−1/kcos(kx)|π0=−1/k(cos(kπ)−cos(k∗0))
if k is odd then,=−1/k(−1−1)=−1/k(−2)=2/k
if k is even then,=−1/k(1−1)=0
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