Answer:
HYMY5XNYRHL,U5HCUXSVUHK CUIUUVBTQ0 I IEGIPHUAI YJ0H ITHUIO OHJR IMPJEHKLJJJKQJKBQJ JTK4JETHION JT B J2OYJEHJ QYI YJ2ILKBJEYJKBN BCGHB JHWBU6HOH4L6IU5YIH 45HKH IVTLTGJITTYIHG6I HTITH3H1JH5J 4HI HUU5HI
Step-by-step explanation:
JUI4GT ITHKJ4JHUEUOERSUIHIATJOIRJI TUOTHEHTEI ETHJKLGEHINGKJBITHITJTRIH WI WHIWK JGERKHBORHKRGHJRJHTHI HWRJ4IHGUERWGJWBURHRIHRURWBNGIUBU
Answer:
The third one....
it fulfill all required characteristics of lines given.
We want to solve the two equations

and

First equation.
Take natural log of each side.

Note that ln(e) = 1 by definition.
Answer: x = 1.79 (nearest hundredth)
Second equation.
Take natural log of each side.

Answer: y = -2.21 (nearest hundredth)
Answer:
x = 1.2
Step-by-step explanation:
Essentially, because ABCDE and JKLMN are similar, their corresponding sides have a common ratio. To find x, we can simply the ratio between NJ and its corresponding side equal to the ratio of another pair of corresponding sides.


3x = 3.6
x = 1.2
T-T this took waaaaaay too long to be helpful but I hope it is anyways!
17.5
2pi times the radius times the degree measurment/360