All categories

3 years ago

Ting

Mathematics

2 answers:

Eddi Din [679]3 years ago

8 0

Answer:

Difference of Expression

5a+ 3b -6c -( 20 -4b +13c)

= 5a +3b -6c -20 +4b -13c

= 5a +3b +4b -6c -13c -20

= 5a +7 b - 19 c -20

TiliK225 [7]3 years ago

7 0

In this question, you would be solving the expression by combining like terms.

Solve:

(5a + 3b - 6c) - (20 - 4b + 13c)

Distribute the negative to the variables inside the parenthesis.

5a + 3b - 6c - 20 + 4b - 13c

Combine like terms.

5a + 7b - 6c - 20 - 13c

5a + 7b - 19c - 20

You can't combine anymore like terms now, so your answer would be 5a + 7b - 19c - 20

Answer:

5a + 7b - 19c - 20

You might be interested in

Trevor has $9100 in an investment account. He withdrew all of his money from the account. He spent $1100 on a plane ticket to Pa

Ilya [14]

Answer:

$6,400

Step-by-step explanation:

9100-1100

8000

8000×1/5

$1600

8000-1600

$6,400

3 0

2 years ago

How do you solve this equation 5/2c = 8 1/3

OLga [1]

Answer:

all work is shown and pictured

8 0

3 years ago

Find the slope of a line parallel to each given line Y equals -1÷3 X +3

g100num [7]

The answer for this will be

-1/3x+3

4 0

3 years ago

An aircraft has a total time in service of 468 hours. The Airworthiness Directive given was initially complied with at 454 hours

Georgia [21]

Answer:

440 hours

Step-by-step explanation:

In this case the aircraft has completed one cycle of service in the first 454 hours of service. Then making the difference between the hours of service and the hours of the first cycle we have:

Hours of the second cycle= Total time in service- time Airworthiness Directive

=468-454=14

Then we have 14 hours of service and need to accumulate the rest to complete 454. It is

454-14=440

Then we need to accumulate 440 hours additional to complete the Airworthiness Directive .

6 0

3 years ago

A box contains 3 green marbles, 5 blue marbles, and 7 red marbles. Three marbles are selected at random from the box, one at a t

USPshnik [31]

Answer:

The probability is $P(K) = \frac{ 28 }{195}$

Step-by-step explanation:

From the question we are told that

The number of green marbles is $n_g = 3$

The number of red marbles is $n_b = 5$

The number of red marbles is $n_r = 7$

Generally the total number of marbles is mathematically represented as

$n_t = n_r + n_g + n_ b$

$n_t = 7 + 3 + 5$

$n_t = 5$

Generally total number of marbles that are not red is

$n_k = n_g + n_ b$

=> $n_k = 3 + 5$

=> $n_k = 8$

The probability of the first ball not being red is mathematically represented as

$P(r') = \frac{n_k}{n_t}$

=> $P(r') = \frac{ 8}{15}$

The probability of the second ball not being red is mathematically represented as

$P(r'') = \frac{n_k - 1}{n_t -1}$

=> $P(r'') = \frac{ 8 -1 }{15-1}$ (the subtraction is because the marbles where selected without replacement )

=> $P(r'') = \frac{ 7 }{14}$

The probability that the first two balls is not red is mathematically represented as

$P(R) = P(r') * P(r'')$

=> $P(R) = \frac{ 8}{15} * \frac{ 7 }{14}$

=> $P(R) = \frac{ 8 }{30}$

The probability of the third ball being red is mathematically represented as

$P(r) = \frac{n_r}{ n_t -2}$ (the subtraction is because the marbles where selected without replacement )

$P(r) = \frac{7}{ 15 -2}$

=> $P(r) = \frac{7}{ 13}$

Generally the probability of the first two marble not being red and the third marble being red is mathematically represented as

$P(K) = P(R) * P(r)$

$P(K) = \frac{ 8 }{30} * \frac{7}{ 13}$

=> $P(K) = \frac{ 28 }{195}$

6 0

3 years ago