Box A has 12 balls and Box B has 8 balls.
OR
Box A has 60 balls and Box B has 40 balls.
OR
Box A has 48 balls and Box B has 32 balls.
Answer:
N=958
Step-by-step explanation:
19(n − 927) = 589
19n - 17,613 = 589
Answer:
What is the probability that a randomly selected family owns a cat? 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%
Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:
Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)
So, 30% of the families own a dog = .30*100 = 30
20% of the families that own a dog also own a cat = 0.2*30 = 6
34% of all the families own a cat = 0.34*100 = 34
Dogs and cats: 6
Only dogs: 30 - 6 = 24
Only cats: 34 - 6 = 28
Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42
What is the probability that a randomly selected family owns a cat?
34/100 = 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
A = doesn't own a dog
B = owns a cat
P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%
The point (x1,y1) on the graph of f(x) is the point (x1-a,y1) for the function
f(x+a)
(-8,-7)=(x1,y1)→x1=-8, y1=-7
f(x-4)=f(x+a)→a=-4
(x1-a, y1)=(-8-(-4), -7)=(-8+4, -7)=(-4,-7)
<span>The corresponding point for the fuction f(x -4) is (-4,-7)</span>
Label the width: 4ft
Label the length: 12ft (4ft for each segment).
Perimeter=12+12+4+4=32ft