What factors of 20 go into 50

A puppy and kitten are 180 meters apart when they see each other. The puppy can run at a speed of 25 meters per second, while th

Gnom [1K]

It seems it should be the other way... . How soon will the puppy catch up with the kitten.

The way you have it the kitten will never catch the pup. There is already 180m between them so, the distance will only increase because the puppy runs faster than the cat.

If the puppy runs after the cat, will eventually catch up with it and can be calculated. Not the other way around.

If the pup runs after the cat, the distance between them will decrease and the pup will catch the cat.

RT = D kitten

RT = D+180 puppy

20T = D

25T = D + 180

Substitution

25T = 20T +180

5T = 180

T = 36s

7 0

3 years ago

Could I have some help please

solmaris [256]

Since AB=AD, the triangle on the left is isosceles and has two 35 degree angles. Since the sum of all the interior angles is 180 deg,

x = 180 deg - 2(35 deg) = 110 deg (answer)

3 0

3 years ago

A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w

melamori03 [73]

Answer:

The hypothesis is:

H₀: $p_{X}-p_{Y}=0$ .

Hₐ: $p_{X}-p_{Y}$ .

Step-by-step explanation:

Let X = number of men who exercise regularly and Y = number of women who exercise regularly.

The information provided is:

$n_{X}=150\\X=88\\n_{Y}=200\\Y=130$

Compute the sample proportion of men and women who exercise regularly as follows:

$\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587$

$\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65$

The random variable X follows a Binomial distribution with parameters n = 150 and $\hat p_{X}=0.587$ .

The random variable Y also follows a Binomial distribution with parameters n = 200 and $\hat p_{Y}=0.65$ .

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\hat p=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

So, the sampling distribution of the proportion of men and women who exercise regularly follows a Normal distribution.

A two proportion z-test cab be performed to determine whether the proportion of women is more than men who exercise regularly.

The hypothesis for this test cab be defined as:

H₀: The proportion of women is same as men who exercise regularly, i.e. $p_{X}-p_{Y}=0$ .

Hₐ: The proportion of women is more than men who exercise regularly, i.e. $p_{X}-p_{Y}$ .

6 0

3 years ago

Read 2 more answers

The cost of a book is $x what is the expression in terms of x for the number of these books which are bought for $40

spayn [35]

Answer:

In x dollars,

number of book that can be bought = 1

So, In 1 dollar,

number of books that can be bought = 1/x

Hence in 40 dollars,

number of books that can be bought = 40/x

6 0

2 years ago

Read 2 more answers

A safety regulation states that the height hh of a guardrail should be 106 centimeters with an absolute deviation of no more tha

iren [92.7K]

Let us say that h is the height of the guardrail. Therefore the inequality equation that we can generate from this scenario is:

| h – 106 | = ± 7

There are two ways to solve this, either the equation is positive or negative.

When the equation is positive, therefore:

| h – 106 | = 7

h = 7 + 106 = 113 cm

When the equation is negative, therefore:

| h – 106 | = - 7

h = -7 + 106 = 99 cm

So the height must be 99 cm to 113 cm

6 0

3 years ago