Answer: It would be d,15m
Answer:
x=-11, -1, and 3
Step-by-step explanation:
x^3+9x^2-25x-33=0
There are formulas to solve cubics, but that probably is not the way you are expected to go. Here is a trial and error approach that works in this case.
Assume that the cubic can be factored and that the roots are r1, r2, and r3. Then the factored form is
(x-r1)(x-r2)(x-r3)=0
This shows that the constant must equal the product of the roots.
(r1)(r2)(r3)=-33
One possibility is that the roots are integers. In this case, a factor of 33 might work. Prime factorization of 33 gives 3 and 11. Try 3. Then (x-3) is a factor.
Divide the cubic by (x-3). It works. the result is
x^2+12x+11
This has factors of (x+11) and (x+1). Therefore, the roots are 3, -1, and -11
Answer:
y = .75x + 1 or y= 3/4x+1
Step-by-step explanation:
Answer:
Scale factor = 3 : 1
Step-by-step explanation:
Scale factor of figure = 
From the graph attached,
Scale factor = 
= 
[Since size of every square of the graph is same]
= 3
Therefore, scale factor of figure A to figure B is 3.
In other words ratio of the size of figure A to figure B will be 3 : 1.
We know that
side AB is parallel to side CD
then
∠A=∠D
∠B=∠C
therefore
(2x+6)/10=(x+6)/8-------------> 8*(2x+6)=10*(x+6)------> 16x+48=10x+60
16x-10x=60-48----------> 6x=12---------> x=2
so
AE=2x+6-------> 2*2+6--------> AE=10
the answer is AE=10 units
