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jarptica [38.1K]
4 years ago
13

When Wesley began first grade, he was 44 3/8 inches tall. At the end of the year, he was 45 1/4 inches tall. How much had Wesley

Grown.
Mathematics
1 answer:
nikitadnepr [17]4 years ago
3 0
So start:44 3/8 end: 45 1/4
so 44 3/8+x=45 1/4
subtract 44 3/8 from both sides
x=grow=45 1/4-44 3/8
so convert to fractions
45=180/4
45 1/4=181/4

44=352/8
44 3/8=355/8
181/4=362/8
x=362/8-355/8=7/8 inch he grew


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brilliants [131]

Answer:

m<4=40

Step-by-step explanation:

Supplementary angles form 180 degrees

m<3 is vertical to the 50 degree angle which is equal.

so. m<3=50

m<5=90

90+50=140

180-140=40

m<4=40

4 0
3 years ago
If 50 bicycles cost $100.50, then how many bicycles could you get for $45?
8_murik_8 [283]
Answer


22 WHOLE bicycles


Step by step explanation

If you divide 100.50 by 50 you get how much it cost for each bicycle which is 2.01 and when you divided 45 by 2.01 you get 22 and a bunch of random numbers but you can’t get that part of a bicycle because you are not going to cut a bicycle into pieces so you will be able to buy 22 and you will have some left over money but that doesn’t matter you can get 22 whole bicycle with 45 dollars
5 0
3 years ago
Read 2 more answers
15.3+x=1.3-x so how do I solve it
anzhelika [568]

Answer:

-7

Step-by-step explanation:

Let's try getting rid of the numbers to isolate the x.

Add x on both sides to get rid of the x on the right side and to get 2x on the left side. This leaves us with 15.3 + 2x = 1.3

Subtract 15.3 on both sides to get rid of the 15.3 on the left side.

This would leave us with 2x = -14

Divide 2 on both sides to isolate the x.

The answer is x = -7

3 0
4 years ago
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Evaluate the expression, when x = 3.2x + 4(x - 2)a910ObocOd118
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4 0
1 year ago
A=1/2h(b+c) solve for h
pogonyaev
<span>1) Multiply both sides of the equation by 2:

2(A)=2[1/2h(b+c)
2A=2/2h(b+c)
2A=1h(b+c)
2A=h(b+c)

2) Divide both sides of the equation by (b+c):
(2A)/(b+c)=[h(b+c)]/(b+c)
2A/(b+c)=h
h=2A/(b+c)

 Answer: </span>h=2 \frac{A}{(b+c)}
5 0
4 years ago
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