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Ede4ka [16]
3 years ago
15

3^6/3^_ = 3^4 what is the missing value?

Mathematics
1 answer:
Strike441 [17]3 years ago
8 0
\frac{a^b}{a^c} =a^{b-c}

\frac{3^6}{3^x} =3^4\\\\3^{6-x}=3^4\\6-x=4\\-x =-2\\\\x=2
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Do solve this you use PEMDAS. This stands for:
Parenthesis
Exponents
Multiplication
Division
Addition
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Because there are no parentheses or exponents in this equation, we go straight to the division.

1) 8 divided by 4 equals two so we rewrite the equation. 5+6 x 2 - 2 + 7.

2) Next in order of pemdas is multiplication. Yes I know that in pemdas multiplication does come before division but it doesn’t matter in this problem which you do first. So now we do 6 x2 =12. We then rewrite the equation 5+12-2+7.

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So the final answer is: 22
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Step-by-step explanation:

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