Answer:
wish i could help
Step-by-step explanation:
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The wrong statement: The volume or the smaller cone cannot be determined because its height is unknown.
We already know that the larger cone has a height of 8 cm and that the smaller cone is just 1/4 of 8 cm.
8×1/4 = 2 cm.
You can still find its volume by using the formula 1/3πr^2.
We take each number as x = 2x 3x 4x
(2x)³+(3x)³+(4x)³=33957
8x³+27x³+64x³=33957
99x³=33957
x³=33957÷99
=∛343
x=7
2x=2×7=14
3x=3×7=21
4x=4×7=28
=the three numbers are 14,21,28
Answer:

Step-by-step explanation:
We are told that the area of the bag can be represented by the function
and as the bag is raised up its height can be represented by the function
.
Since we know that we can find volume of cuboid by multiplying base area to its height. We are given area and height of bag as functions. Now we will find volume of the bag by multiplying these functions.

After using distributive property we will get,


Therefore, the collapsible bag can hold
grain.