3 years ago

Write an equation of a parabola with vertex at the origin and the given focus (6,0)

Mathematics

1 answer:

Masteriza [31]3 years ago

4 0

Answer:

Step-by-step explanation:

eq. of a parabola with vertex at origin and focus (a,0) is

y²=4ax

a=6

so y²=4×6×x

or y²=24 x

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How do I work out this equation?

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3 years ago

LM=9, NR=16, SR=8. Find the perimeter of △SMP.

Amanda [17]

Answer:

<h2>perimeter of △SMP = 25</h2>

Step-by-step explanation:

The perimeter of the triangle △SMP is the sum of al the sides of the triangle.

Perimeter of △SMP = ||MS|| + ||MP|| + ||SP||

Note that the triangle △LRN, △LSM, △MPN and △SRP are all scalene triangles showing that their sides are different.

Given LM=9, NR=16 and SR=8

NR = NP+PR

Since NP = PR

NR = NP+NP

NR =2NP

NP = NR/2 = 16/2

NP = 8

From △LSM, NP = PR = <u>MS</u><u> = 8</u>

Also since LM = MN, MN = 9

From △SRP, SR = RP = <u>PS = 9</u>

Also SR =<u> MP = 8</u>

From the equation above, perimeter of △SMP = ||MS|| + ||MP|| + ||SP||

perimeter of △SMP = 8+8+9

perimeter of △SMP = 25

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3 years ago

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