D=event that chip selected is defective
d=event that chip selected is NOT defective
Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154
Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20
I think the answer might be 72
Answer:
the answer would be A.
Step-by-step explanation:
because the number of books(n) times 2, because they have twice the number of books divided hy fifteen so fifteen is below the line. im bad at explaning trust me
ANSWER:
The surface area of the star is 3.2700 x 
square kilometres.
EXPLANATIONS:
Diameter of the star = 1.8083 x 
Km.
Surface area of the star = 4
Where n is the radius of the star.
So that;
n = 
= 0.90415 x
n = 0.90415 x Km
Thus,
Surface area = 4 x 
= 326994889
Surface area = 3.2700 x 
Therefore, the surface area of the star is 3.2700 x square kilometres.
Direct variation is y=kx, inverse variation is y=k/x....
-5y=-2x divide both sides by -5
y=2.5x
So this is a direct variation with a constant of 2.5
