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Alexus [3.1K]
3 years ago
11

Fingernails grow 1.5 inches per year. How long would it take to grow them 37 inches

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
8 0
1,5\ inches\ \ in\ \ 1\ year\\
37\ inches\ \ \ in\ \ \ x \ years \\\\Making\ ratio\\
1,5-1\\
37-x\\\\\
1,5x=37\ \ \ |Divide\ by\ 1,5\\
x=27,7\ \ \ \ \\\\\
It\ will \take\ 27,7\ years.
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Two cars leave town at the same time going in the same direction on the same road.One travels 32 mi/h and the other travels 47 m
gladu [14]
In 4.6 hours they will be 69 miles apart 
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3 years ago
Cho tam giác ABC cân tại A trung tuyến AM.Biết BC=6cm,AM=4cm .Tính độ dài các cạnh AB và AC
abruzzese [7]

Vì tam giác ABC cân tại A (gt) mà AM là đg trung tuyến nên AM đồng thời là đg cao của t/giác đó:

AM là trung tuyến của t/giác ABC nên M là trung điểm BC:

=> BM =BC/2 =6:2=3(cm)

Xét tam giác AMB vuông tại M

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7 0
3 years ago
Geometry sucks please help ​
ehidna [41]

Answer:

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  b. AE = 1.6 ft

Step-by-step explanation:

SOH CAH TOA reminds you of the relationship between trig functions and right triangle sides.

a. Cos = Adjacent/Hypotenuse

  cos(28°) = BE/BA = 3 ft/BA

Multiplying by BA and dividing by cos(28°), you get ...

  BA = (3 ft)/cos(28°) ≈ 3.4 ft

___

b. Tan = Opposite/Adjacent

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Multiplying by 3 ft, you get ...

  AE = (3 ft)·tan(28°) ≈ 1.6 ft

5 0
3 years ago
PLSSS HELP WILL GIVE BRAINLIEST FOR FIRST CORRECT ANSWER!!!!!!!!!
Kryger [21]

Answer:

A fair die has 6 sides.

There are 3 odd numbers on a fair die so the probability would be 3/6

There are 4 numbers greater than 2 on a fair die o the probability of that would be 4/6

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6 0
3 years ago
The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
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