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Brums [2.3K]
3 years ago
12

Emmanuel bought 28 lb of potting soil this week. This amount is 4 lb. more than twice the amount of potting soil he bought last

week. Answer the following questions to find the number of pounds of soil Emmanuel purchased last week.
(b) Let p represent the unknown information. Write an equation to model the problem.
show your work
Mathematics
2 answers:
musickatia [10]3 years ago
7 0

Answer:

7 (28lb ÷ 4lb = 7lb)

Step-by-step explanation:

28÷4= p

makvit [3.9K]3 years ago
3 0
An equation for this:

28 * 2 + 4 = p

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1.) 72.75

2.)77.25

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Step-by-step explanation:

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3 years ago
A boiler room has the shape of a rectangular prism. The area of the floor of the room is 112 square feet. The length of the room
Naddik [55]

Answer:

Length = 16 feet.

Width = 7 feet

Height = 8 feet

Volume = 896 cubic feet.

Step-by-step explanation:

There is a rectangular prism boiler room. 112 square feet is the floor area of the room.

Let the length of the room is L feet and width is W feet.

So, LW = 112 ...... (1)

Now, given that L = 2 + 2W ........ (2) , hence, from equation (1) we get  

(2 + 2W)W = 112

⇒ 2w + 2w² = 112

⇒ W² + W - 56 = 0

⇒ (W +8)(W - 7) = 0

⇒ W = 7 feet. {Neglecting the negative root as W can not be negative}

Hence, from equation (2) we get L = 2W + 2 = 16 feet.

Now, 1 foot more than the width is the height H.

Hence, H = 7 + 1 = 8 feet.

Therefore, the volume of the room is, V = LWH = 16 × 7 × 8 = 896 cubic feet. (Answer)

5 0
3 years ago
Permiter math equation help pls
Anestetic [448]

Hi

First dont panic. this one is pretty easy.

you known that the perimeter is the addition of every sides of a figure.

you have the total perimeter : 84.6

so now you just have to withdraw every side you have to the total , and the missing measure will be the result.

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3 years ago
Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen
Jobisdone [24]

Parameterize S by the vector function

\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k

so that the normal vector to S is given by

\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k

with magnitude

\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}

In this case, the normal vector is

\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k

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\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx

where T is the region in the x,y plane over which S is defined. In this case, it's the triangle in the plane z=0 which we can capture with 0\le x\le8 and 0\le y\le\frac{8-x}2, so that we have

\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}

5 0
3 years ago
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