Step-by-step explanation:
so, he will not wear any pants ? socks ? not to mention underwear ?
anyway, we have to deduct the $35 for the shoes, as he is seemingly buying them in any case.
so, we are left with 100 - 35 = $65 for shirts.
as one shirt costs $15, we need to see how often 15 fits into 65, as that is the answer how many shirts he can buy for this money.
65 / 15 = 4.333333333...
since he cannot buy a part shirt, we can only rely on the integer part of the calculation.
so, he can buy 4 shirts and will have $5 left.
Answer:
j = 0 or j = 30
Step-by-step explanation:
j² - 30j = 0
Factorise j out of both terms on the left side.
j (j-30) = 0
Apply zero product rule.
j = 0 or j-30 = 0
Find the value of j.
j = 0 or j = 30
Answer:
1. 
2. 
3. 
4. ![40^{\frac{2}{3}}=4\sqrt[3]{25} =4325](https://tex.z-dn.net/?f=40%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D4%5Csqrt%5B3%5D%7B25%7D%20%3D4325)
5. Step 4: 
6. 
Step-by-step explanation:
Use the following properties:
![a^{\frac{x}{y} } =\sqrt[x]{a^{y} }](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7Bx%7D%7By%7D%20%7D%20%3D%5Csqrt%5Bx%5D%7Ba%5E%7By%7D%20%7D)
![\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bab%7D%20%3D%5Csqrt%5Bn%5D%7Ba%7D%20%5Csqrt%5Bn%5D%7Bb%7D)
So:
1. ![27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9](https://tex.z-dn.net/?f=27%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D%20%3D%5Csqrt%5B3%5D%7B27%5E%7B2%7D%7D%20%3D%5Csqrt%5B3%5D%7B729%7D%20%7D%3D9)
2. 
3. ![(-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27](https://tex.z-dn.net/?f=%28-243%29%5E%7B%5Cfrac%7B3%7D%7B5%7D%20%7D%20%3D%5Csqrt%5B5%5D%7B-243%5E%7B3%7D%20%7D%20%3D%5Csqrt%5B5%5D%7B-14348907%7D%20%3D-27)
4. ![40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325](https://tex.z-dn.net/?f=40%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B40%5E%7B2%7D%20%7D%20%3D%5Csqrt%5B3%5D%7B2%5E%7B6%7D%205%5E%7B2%7D%20%7D%20%3D%5Csqrt%5B3%5D%7B2%5E%7B6%7D%20%7D%20%5Csqrt%5B3%5D%7B5%5E%7B2%7D%20%7D%20%3D2%5E%7B%5Cfrac%7B6%7D%7B3%7D%20%7D%205%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D%20%3D4%20%2A5%5E%7B%5Cfrac%7B2%7D%7B3%7D%20%7D%20%3D4%5Csqrt%5B3%5D%7B5%5E%7B2%7D%20%7D%20%3D4%5Csqrt%5B3%5D%7B25%7D%3D4325)
5. 
6.
![(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}](https://tex.z-dn.net/?f=%28-8c%5E%7B9%7D%20d%5E%7B-3%7D%20%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%20%2A%286c%5E%7B-1%7Dd%5E%7B4%7D%29%5E%7B2%7D%20%3D%5Csqrt%5B3%5D%7B-8%7D%20c%5E%7B3%7D%20d%5E%7B-1%7D%2036c%5E%7B-2%7D%20d%5E%7B8%7D%20%5C%5C%5C%5C-2c%5E%7B3%7D%20d%5E%7B-1%7D%2036c%5E%7B-2%7D%20d%5E%7B8%7D%3D-72cd%5E%7B7%7D)
We know that for all B:
![\csc\text{B}\in(-\infty,-1]\cup[1,\infty)](https://tex.z-dn.net/?f=%5Ccsc%5Ctext%7BB%7D%5Cin%28-%5Cinfty%2C-1%5D%5Ccup%5B1%2C%5Cinfty%29)
So the answer is 0,5 (b.)
I'm assuming it is asking for surface area.
SA = 2(lw) + 2(hw) + 2(lh)
SA = 2(3*4) + 2(4*8) + 2(3*8)
SA = 2(12) + 2(32) + 2(24)
SA = 24 + 64 + 48
SA = 136 square feet
