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zlopas [31]
4 years ago
7

Two mechanics worked on a car. The first mechanic worked for 10 hours, and the second mechanic worked for 5 hours. Together they

charged a total of $1200. What was the rate charged per hour by each mechanic if the sum of the two rates was $165 per hour?
Mathematics
1 answer:
nignag [31]4 years ago
4 0

Answer:

Step-by-step explanation:

Let a represent the charges made hourly by Mechanic 1 and b represent that of Mechanic 2;

a + b = 165, a = 165 - b

10a + 5b = 1200

substitute the value of a in the second equation;

10(165 - b) + 5b = 1200

1650 - 10b +5b = 1200

1650 - 5b = 1200

-5b = 1200 - 1650

-5b = -450

b = 450/5

b = $90/hr

If mechanic 2 charged $90/hr,

a + 90 = 165

a = 165 - 90

a = $75/hr being the hourly rate charged by mechanic 1.

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I neeeeedds helllppp
kvasek [131]

Wow. 16,000 a month? Where does he work? Can I come intern?

But anyways, 1/4 of $16000 is $4000 so he has $12,000 left. 3/10 of $12000 is $3600 so he has $8400 left. 5/21 of $8400 is $2000 so therefore he has $6400 left.

3 0
4 years ago
All of the points in the picture are on the same line,
sammy [17]

Answer:

m=2

Step-by-step explanation:

use points (2,2) and (6,10)

(find y of slope)10-2=8

(find x of slope)6-2=4

8/4=2

5 0
3 years ago
In a math class with 27 students, a test was given the same day that an assignment was due. There were 17 students who passed th
timama [110]

Answer:

The probability that a student who completed the homework failed the test is 0.211.

Step-by-step explanation:

The probability of an event <em>E</em> is the ratio of the favorable number of outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

The conditional probability of an event <em>A</em> given that another event <em>B</em> has already occurred is:

P(A|B)=\frac{P(A\cap B)}{P(B)}

Denote the events as follows:

P = a student passes the test

F = a student fails the test

X = a student completes the assignment

Y = a student does not completes the assignment

From the information provided the summary table is as follows:

             P            F         Total

 X         <u>15</u>           <u>4</u>           19

 Y          <u>2</u>            <u>6</u>            <u>8</u>

Total      17          <u>10</u>          27

Compute the probability that a student completed the assignment and failed the test as follows:

P(X\cap F)=\frac{n (X\cap F)}{N}=\frac{4}{27}

Compute the probability that a student completed the assignment as follows:

P(X)=\farc{19}{27}

Compute the probability that a student failing the test given that the student completed the assignment as follows:

P(F|X)=\frac{P(X\cap F)}{P(X)}=\frac{4/27}{19/27}=\frac{4}{19}=0.21053\approx 0.211

Thus, the probability that a student who completed the homework failed the test is 0.211.

7 0
3 years ago
A 0. 0427 kg racquetball is moving 22. 3 m/s when it strikes a stationary box. The ball bounces back at 11. 5 m/s, while the box
andreyandreev [35.5K]

To solve the question we must know about the conservation of momentum.

<h2>Conservation of Momentum</h2>

According to the law of conservation of momentum, when two bodies collide with each other then their momentum is conserved if no external force acts on the system. therefore, the combined momentum of the two objects before collision will be equal to the combined momentum of the two objects after the collision.

the momentum of the two objects before the collision

                       = momentum of the two objects after the collision

The mass of the box is 0.30141 kg.

<h2>Explanation</h2>

Given to us

  • Mass of racquetball, m = 0.0427 kg,
  • Velocity of racquetball before Collision,  \bold{u_1} = 22.3 m/s,
  • Velocity of box before Collision,\bold{ u_2}  = 0 m/s,
  • Velocity of racquetball after Collision, \bold{v_1} = 11.5 m/s,
  • Velocity of box after Collision, \bold{v_2} = 1.53 m/s,

<h3>Assumption</h3>

Let the mass of the box be M.

<h3>Conservation Of Momentum</h3>

Momentum before collision = Momentum after collision

mu_1 + Mu_2 = mv_1 + Mv_2

given, the box was stationary before the collision,

mu_1 + Mu_2 = mv_1 + Mv_2\\\\&#10;mu_1 + 0 = mv_1 + Mv_2\\\\&#10;mu_1  - mv_1 = Mv_2\\\\&#10;M= \dfrac{mu_1  - mv_1}{v_2}

Substituting the values,

M= \dfrac{mu_1  - mv_1}{v_2}\\\\&#10;M = \dfrac{(0.0427 \times 22.3)  - (0.0427\times 11.5)}{1.53}\\\\&#10;M = 0.30141\ kg

Hence, the mass of the box is 0.30141 kg.

Learn more about Conservation of Momentum:

brainly.com/question/2141713

3 0
3 years ago
He ratio of Evan’s red toy cars to blue toy cars is 3 : 4. Evan has 12 red toy cars. How many blue toy cars does Evan have?
julsineya [31]
D, this is because you times the 3 red cars by 4 to get to 12 red cars so you times the 4 blue cars by 4 to get 16 blue cars.
8 0
4 years ago
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