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antoniya [11.8K]
4 years ago
7

I neeeeedds helllppp

Mathematics
1 answer:
kvasek [131]4 years ago
3 0

Wow. 16,000 a month? Where does he work? Can I come intern?

But anyways, 1/4 of $16000 is $4000 so he has $12,000 left. 3/10 of $12000 is $3600 so he has $8400 left. 5/21 of $8400 is $2000 so therefore he has $6400 left.

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Multiply. (w-7) (w+4)
olganol [36]
(w - 7)(w + 4)

w^2 - 7w + 4w - 28

w^2 - 3w - 28
3 0
3 years ago
Read 2 more answers
In a random sample of 2500 sports fans, 61% prefer basketball over soccer.
timama [110]

The margin of error is a statistic that expresses how much random sampling error there is in a survey's results. The Margin of error in this survey is 1%.

<h3>What is the margin of error?</h3>

The margin of error is a statistic that expresses how much random sampling error there is in a survey's results. The wider the margin of error, the less confident one should be that a poll result reflects the outcome of a population-wide survey.

The random sample of 2500 sports fans, out of which 61% prefer basketball over soccer, therefore, we can write n=2500 and p=0.61. Thus, the margin of error can be written as,

MOE=\sqrt{\dfrac{\hat p(1-\hat p)}{n}} = \sqrt{\dfrac{0.61(1-0.61)}{2500}} = 0.00975 = 0.975\% \approx 1\%

Hence, the Margin of error in this survey is 1%.

Learn more about Margin of Error:

brainly.com/question/13990500

#SPJ1

7 0
2 years ago
A house worth $150000 in 1999 increased by a constant rate to its value of $255 000 in 2007. Calculate the home's annual rate of
son4ous [18]

Answer:

13125 per year

Step-by-step explanation:

2007-1999=8

255000-150000=105000

105000÷8=13125

4 0
3 years ago
If N=10 then what is 2n+4
SOVA2 [1]
If n is ten then the expression would change to 
2(10)+4
20+4
so your answer would be 24
3 0
3 years ago
Read 2 more answers
Use induction to show that 12 + 22 + 32 + ... + n2 = n(n+1)(2n+1)/6, for all n &gt; 1.
dlinn [17]

Answer with Step-by-step explanation:

Let P(n)=1^2+2^2+3^2+.....+n^2=\frac{n(n+1)(2n+1)}{6}

Substitute n=2

Then  P(2)=1+2^2=5

P(2)=\frac{2(2+1)(4+1)}{6}=5

Hence, P(n) is true for n=2

Suppose that P(n) is true for n=k >1

P(k)=1^2+2^2+3^2+...+k^2=\frac{k(k+1)(2k+1)}{6}

Now, we shall prove that p(n) is true for n=k+1

P(k+1)=1^2+2^2+3^2+...+k^2+(k+1)^2=\frac{(k+1)(k+2)(2k+3)}{6}

LHS

P(k+1)=1^2+2^2+3^2+.....+k^2+(k+1)^2

Substitute the value of P(k)

P(k+)=\frac{k(k+1)(2k+1)}{6}+(k+1)^2

P(k+1)=(k+1)(\frac{k(2k+1}{6})+k+1)

P(k+1)=(k+1)(\frac{2k^2+k+6k+6}{6})

P(k+1)=(k+1)(\frac{2k^2+7k+6}{6})

P(k+1)=(k+1)(\frac{2k^2+4k+3k+6}{6})

P(k+1)=\frac{(k+1)(k+2)(2k+3)}{6}

LHS=RHS

Hence, P(n) is true for all n >1.

Hence, proved

4 0
3 years ago
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