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2 years ago

Someone please help me

Mathematics

1 answer:

pshichka [43]2 years ago

3 0

That is C and B. The missing lengths

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Consider triangle WXY... which statement about the angles is true?

Brrunno [24]

Answer: The correct option is (A) Angle W is greater than angle Y.

Step-by-step explanation: Given that the measures of the three sides of a triangle XYZ are as follows:

XY = 10 units,

WY = 14 units,

WX = 5 units.

We are to select the correct statements regarding the angles of ΔXYZ.

Writing the lengths of the sides in ascending order, we have

$5$

Since the angle opposite to a smaller side of a triangle is smaller, so from inequality (i), we get

$WX$

Option (A) is "Angle W is greater than angle Y".

This option is correct, because we have ∠W > ∠Y.

Option (B) is "Angle Y is the largest angle".

This is incorrect because ∠X is the largest angle.

Option (C) is "Angle X is smaller than angle W"

This is incorrect because ∠X is the largest.

Option (D) is "Angle W is the smallest angle".

This is incorrect because ∠Y is the smallest.

Thus, (A) is the correct option.

5 0

3 years ago

Read 2 more answers

A foreign student club lists as its members 2 Canadians, 3 Japanese, 5 Italians, and 2 Germans. If a committee of 4 is selected

Fittoniya [83]

Answer:

(a) The probability that the members of the committee are chosen from all nationalities $=\frac{4}{33}$ =0.1212.

(b)The probability that all nationalities except Italian are represent is 0.04848.

Step-by-step explanation:

Hypergeometric Distribution:

Let $x_1$ , $x_2$ , $x_3$ and $x_4$ be four given positive integers and let $x_1+x_2+x_3+x_4= N$ .

A random variable X is said to have hypergeometric distribution with parameter $x_1$ , $x_2$ , $x_3$ , $x_4$ and n.

The probability mass function

$f(x_1,x_2.x_3,x_4;a_1,a_2,a_3,a_4;N,n)=\frac{\left(\begin{array}{c}x_1\\a_1\end{array}\right)\left(\begin{array}{c}x_2\\a_2\end{array}\right) \left(\begin{array}{c}x_3\\a_3\end{array}\right) \left(\begin{array}{c}x_4\\a_4\end{array}\right) }{\left(\begin{array}{c}N\\n\end{array}\right) }$

Here $a_1+a_2+a_3+a_4=n$

${\left(\begin{array}{c}x_1\\a_1\end{array}\right)=^{x_1}C_{a_1}= \frac{x_1!}{a_1!(x_1-a_1)!}$

Given that, a foreign club is made of 2 Canadian members, 3 Japanese members, 5 Italian members and 2 Germans members.

$x_1$ =2, $x_2$ =3, $x_3$ =5 and $x_4$ =2.

A committee is made of 4 member.

N=4

(a)

We need to find out the probability that the members of the committee are chosen from all nationalities.

$a_1$ =1, $a_2$ =1, $a_3$ =1 , $a_4$ =1, n=4

The required probability is

$=\frac{\left(\begin{array}{c}2\\1\end{array}\right)\left(\begin{array}{c}3\\1\end{array}\right) \left(\begin{array}{c}5\\1\end{array}\right) \left(\begin{array}{c}2\\1\end{array}\right) }{\left(\begin{array}{c}12\\4\end{array}\right) }$

$=\frac{2\times 3\times 5\times 2}{495}$

$=\frac{4}{33}$

=0.1212

(b)

Now we find out the probability that all nationalities except Italian.

So, we need to find out,

$P(a_1=2,a_2=1,a_3=0,a_4=1)+P(a_1=1,a_2=2,a_3=0,a_4=1)+P(a_1=1,a_2=1,a_3=0,a_4=2)$

$=\frac{\left(\begin{array}{c}2\\2\end{array}\right)\left(\begin{array}{c}3\\1\end{array}\right) \left(\begin{array}{c}5\\0\end{array}\right) \left(\begin{array}{c}2\\1\end{array}\right) }{\left(\begin{array}{c}12\\4\end{array}\right) }+\frac{\left(\begin{array}{c}2\\1\end{array}\right)\left(\begin{array}{c}3\\2\end{array}\right) \left(\begin{array}{c}5\\0\end{array}\right) \left(\begin{array}{c}2\\1\end{array}\right) }{\left(\begin{array}{c}12\\4\end{array}\right) }$ $+\frac{\left(\begin{array}{c}2\\1\end{array}\right)\left(\begin{array}{c}3\\1\end{array}\right) \left(\begin{array}{c}5\\0\end{array}\right) \left(\begin{array}{c}2\\2\end{array}\right) }{\left(\begin{array}{c}12\\4\end{array}\right) }$

$=\frac{1\times 3\times 1\times 2}{495}+\frac{2\times 3\times 1\times 2}{495}+\frac{2\times 3\times 1\times 1}{495}$

$=\frac{6+12+6}{495}$

$=\frac{8}{165}$

=0.04848

The probability that all nationalities except Italian are represent is 0.04848.

6 0

3 years ago

Solve for W:<br><br> 69=5w+9

Trava [24]

To solve for w, you would take 9 and subtract that from the 69. after that you end up with 60=5w to find w, divide both sides by 5. 60 divided by 5 is 12, giving you your answer .

6 0

3 years ago

Read 2 more answers

What is the Mean, Q1, Med, Q3, and max of the numbers [1,1,3,3,3,9,10,10,11,11,12,12,12,15]

Naddik [55]

Answer:

Hi! The answer is Mean: 8.1, Q1: 3, Med: 10, Q3: 12, Max: 14

Step-by-step explanation:

☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆

☆Brainliest is greatly appreciated!☆

Hope this helps!!

Stay Safe!!

- Brooklynn Deka

5 0

3 years ago

1/10x+9/10=1/10(BLANK)

Sonja [21]

Answer:

x=-8

Step-by-step explanation:

1 Simplify 1/10x to x/10.

x/10 + 9/10 = 1/10

2 Join the denominators.

x+9/10 = 1/10

3 Multiply both sides by 10.

x+9 = 1/10×10

4 Cancel 10.

x+9=1

5 Subtract 9 from both sides.

x=1-9

6 Simplify 1-9 to -8.

x=-8

4 0

2 years ago