Question

Given the equation p = s Subscript 1 Baseline t minus 2 Subscript 2 Baseline t, which equation is solved for t? t = p (s Subscript 1 Baseline minus s Subscript 2 Baseline) t = p minus s Subscript 1 Baseline minus s Subscript 2 t = StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction t = StartFraction p Over s Subscript 1 Baseline + s Subscript 2 Baseline EndFraction
A. t = p (s Subscript 1 Baseline minus s Subscript 2 Baseline)
B. t = p minus s Subscript 1 Baseline minus s Subscript 2
C. t = StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction
D. t = StartFraction p Over s Subscript 1 Baseline + s Subscript 2 Baseline EndFraction

Answer 1

Answer:

Option C) is correct

That is t=StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction

It also can be written as $t=\frac{p}{s_{1}-s_{2}}$

Step-by-step explanation:

Given equation can be written as below:

$p=s_{1}t-s_{2}t$

Now to solve the equation for t:

$p=s_{1}t-s_{2}t$

Taking common term t outside on RHS we get

$p=(s_{1}-s_{2})t$

$\frac{p}{s_{1}-s_{2}}=t$

Rewritting the above equation as below

$t=\frac{p}{s_{1}-s_{2}}$

Therefore option C) is correct

That is t=StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction

It also can be written as $t=\frac{p}{s_{1}-s_{2}}$

Answer 2

Answer:

C. t = StartFraction p Over s Subscript 1 Baseline minus s Subscript 2 Baseline EndFraction

Step-by-step explanation: