Highest common factor of 63 and 45 is 9.
Therefore there can be 9 bouquets each with 5 roses and 7 carnations
We need more detail I will help when i get a real question
Answer:
The p-value for this hypothesis test is P=0.015.
Step-by-step explanation:
In this case we have hypothesis test for the mean, with standard deviation of the population unknown.
The null hypothesis we want to test is
To work with this test we have a sample of size n=20, sample mean=91 and sample standard deviation=21.
First, we estimate the standard deviation of the population
Then, because we have an estimated standard deviation, we have to calculate the statistics t.
We can look up this value of t in a t-table to know the probability of this value, taking into account 19 degrees of freedom:
The p-value or the probability of P(t>2.342) is 0.01511.
This value P=0.0151 is compared to the significance level (0.05). Since the probability value (0.0151) is less than the significance level (0.05) the effect is statistically significant. Since the effect is significant, the null hypothesis is rejected.