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Alekssandra [29.7K]
3 years ago
9

Simplify the expression to a +bi form: (-12+4i)+(2-2i)

Mathematics
2 answers:
ololo11 [35]3 years ago
8 0

Answer:

Step-by-step explanation:

-12 + 2 + 4i - 2i

-10 + 2i

AfilCa [17]3 years ago
7 0

Answer:

-10+2i

Step-by-step explanation:

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Can you do it step by step for me
liraira [26]

Answer:

= 10

Step-by-step explanation:

r + (s+1)^{2} ÷ 3

if, r = 7 and s = 2

SO..

7 + (2+1)^{2} ÷ 3

..

Add 2 and 1 to get 3.

7 + \frac{3^{2} }{3}

Calculate 3 to the power of 2 and get 9.

7 + \frac{9}{3}

Divide 9 by 3 to get 3.

7 + 3 = 10

7 0
2 years ago
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A scientist is observing the grizzly bear population in two state parks. The parks each have 150 bears when he begins observing
Mars2501 [29]
Nothing to drag; nowhere to drag it to.

Park A's population can be modeled by
.. y = 150*1.2^x

Park B's population can be modeled by
.. y = 150*0.8^x
5 0
3 years ago
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Diego's mother is twice as old as he is she is also as old as the sum of the ages of diego and both of his younger twin brothers
OLEGan [10]
2d = d + 11 + 11 = d + 22
d = 22
Diego is 22 years old.
7 0
3 years ago
Ken, the camp cook, makes 3 meals for every camper. The equation y= 3x shows the number of meals he makes, which depends on the
Natasha2012 [34]

Answer:

C.

Step-by-step explanation:

I just took the quiz

4 0
2 years ago
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How many solutions does the equation have, x1 + x2 + x3 = 10 , where x1 , x2, and x3 are non-negative integers?
MAVERICK [17]

Non-negative integers are positive integers or zero.

1. When x_1=0, then there are such possible cases for x_2 and x_3:

  • x_2=0,\ x_3=10;
  • x_2=1,\ x_3=9;
  • x_2=2,\ x_3=8;
  • x_2=3,\ x_3=7;
  • x_2=4,\ x_3=6;
  • x_2=5,\ x_3=5;
  • x_2=6,\ x_3=4;
  • x_2=7,\ x_3=3;
  • x_2=8,\ x_3=2;
  • x_2=9,\ x_3=1;
  • x_2=10,\ x_3=0.

In total 11 solutions for x_1=0.

2. For x_1=1, there are such possible cases for x_2 and x_3:

  • x_2=0,\ x_3=9;
  • x_2=1,\ x_3=8;
  • x_2=2,\ x_3=7;
  • x_2=3,\ x_3=6;
  • x_2=4,\ x_3=5;
  • x_2=5,\ x_3=4;
  • x_2=6,\ x_3=3;
  • x_2=7,\ x_3=2;
  • x_2=8,\ x_3=1;
  • x_2=9,\ x_3=0.

In total 10 solutions for x_1=1.

3. This process gives you

  • for x_1=2 - 9 solutions;
  • for x_1=3 - 8 solutions;
  • for x_1=4 - 7 solutions;
  • for x_1=5 - 6 solutions;
  • for x_1=6 - 5 solutions;
  • for x_1=7 - 4 solutions;
  • for x_1=8 - 3 solutions;
  • for x_1=9 - 2 solutions;
  • for x_1=10 - 1 solution.

4. Add all numbers of solutions:

11+10+9+8+7+6+5+4+3+2+1=66.

Answer: there are 66 possible solutions (with non-negative integer variables)

8 0
3 years ago
Read 2 more answers
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