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3 years ago

Xax^2+bx+c=0 proof

Mathematics

1 answer:

muminat3 years ago

5 0

Answer

a= −bx−c / x2

Step-by-step explanation:

ax2+bx+c=0

Step 1: Add -bx to both sides.

ax2+bx+c+−bx=0+−bx

ax2+c=−bx

Step 2: Add -c to both sides.

ax2+c+−c=−bx+−c

ax2=−bx−c

Step 3: Divide both sides by x^2.

ax2

−bx−c

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The annual increase in height of cedar trees is believed to be distributed uniformly between five and ten inches. Find the proba

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Answer: 0.6000

Step-by-step explanation:

Given : The annual increase in height of cedar trees is believed to be distributed uniformly between 5 and 10 inches.

Then the probability density function:-

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Then , the probability that a randomly selected cedar tree will grow less than 8 inches in a given year will be :-

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3 years ago

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jeka94

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In the figure below, m || n and t is a transversal line. If ∠7 = x +14 and ∠1 = 2x -8, what is ∠4?

nikdorinn [45]

∠4 and ∠1 are opposite angles, and since opposite angles are equal, ∠4 = 2x - 8

(if u need a specific number)

∠1 is corresponding to ∠5, and since corresponding angles are equal, ∠5 = 2x-8

∠7 is supplementary to ∠5, and since supplementary angles add up to 180, x + 14 + 2x - 8 = 180

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3 years ago

Xax^2+bx+c=0 proof ​

Xax^2+bx+c=0 proof