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irina1246 [14]
2 years ago
10

Xax^2+bx+c=0 proof ​

Mathematics
1 answer:
muminat2 years ago
5 0

Answer

a=  −bx−c  / x2

Step-by-step explanation:

ax2+bx+c=0

Step 1: Add -bx to both sides.

ax2+bx+c+−bx=0+−bx

ax2+c=−bx

Step 2: Add -c to both sides.

ax2+c+−c=−bx+−c

ax2=−bx−c

Step 3: Divide both sides by x^2.

ax2

x2

=

−bx−c

x2

a=

−bx−c

x2

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0.25 r – 0.125 + 0.5 r = 0.5 + r . solve for r
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