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irina1246 [14]
3 years ago
10

Xax^2+bx+c=0 proof ​

Mathematics
1 answer:
muminat3 years ago
5 0

Answer

a=  −bx−c  / x2

Step-by-step explanation:

ax2+bx+c=0

Step 1: Add -bx to both sides.

ax2+bx+c+−bx=0+−bx

ax2+c=−bx

Step 2: Add -c to both sides.

ax2+c+−c=−bx+−c

ax2=−bx−c

Step 3: Divide both sides by x^2.

ax2

x2

=

−bx−c

x2

a=

−bx−c

x2

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ra1l [238]

Answer:

The equation in the slope-intercept form will be:

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Step-by-step explanation:

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<h2><u><em>Hope this helps!</em></u></h2>

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