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3 years ago

Find length of PR. TR=x+11

Mathematics

2 answers:

kkurt [141]3 years ago

8 0

Step-by-step explanation:

In a square,

we know that when diagonals bisect each other it is divided into two equal parts

TR = TP

PR = x +11 + x + 11

= 2x + 22

And

Both diagonals are equal so

QS = PR

7x - 3 = 2x + 22

7x - 2x = 22 + 3

5x = 25

x= 25 /5

x = 5

Now

PR = 2 * 5 +22= 10 +22 = 32

ikadub [295]3 years ago

3 0

Answer:

PR = 34

Step-by-step explanation:

The diagonals of a square bisect each other, and are congruent, thus

QS = PR, that is

7x - 8 = x + 11 + x + 11 = 2x + 22 ( subtract 2x from both sides )

5x - 8 = 22 ( add 8 to both sides )

5x = 30 ( divide both sides by 5 )

x = 6

Thus

PR = 2x + 22 = 2(6) + 22 = 12 + 22 = 34

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3 years ago

Circle towns limit form a perfectly circular shape that has a population of 20000 in the population density of 480 people per sq

Alex

Answer:

$D =\frac{P}{\pi X^2}$

And solving for the radius we got:

$X = \sqrt{\frac{P}{\pi D}}$

And replacing the data given we got:

$X = \sqrt{\frac{480 \frac{people}{km^2}}{\pi *20000 people}}= 0.0874Km$

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Step-by-step explanation:

For this case we know the population size $P = 20000$ and we also know the population density $D = 480 \frac{people}{km^2}$

We can assume that the area is a circle. We also know that the formula for the population density is given by:

$D= \frac{P}{A}$

Where P represent the number of people and A the area. Since we are assuming a circle then the area is given by:

$A = \pi X^2$

With X the radius of the circle

And then the populationd density become:

$D =\frac{P}{\pi X^2}$

And solving for the radius we got:

$X = \sqrt{\frac{P}{\pi D}}$

And replacing the data given we got:

$X = \sqrt{\frac{480 \frac{people}{km^2}}{\pi *20000 people}}= 0.0874Km$

And this value converted to meters is $X = 87.40 m$

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4 years ago