so 120 - 39 is 80 then minus the basketball and you get fortyfor
Let the number of reserved tickets = x
Let the number of lawn seats = y
Constraint functions:
Maximum capacity means 
For concert to be held 
means 
Objective functions :
Maximum profit equation p = 65x +40y
Intersection points :
(10000,10000) (20000,0)(2500,2500)(5000,0)
p at (10000,10000) = 65(10000) + 40(10000) = $1050000
p at (20000,0) = 65(20000) + 40(0) = $1300000
p at (2500,2500) = 65(2500) + 40(2500) = $262500
p at (5000,0) = 65(5000) + 40(0) = $325000
Hence maximum profit occurs when all 20000 reserved seats are sold and the profit is $1300000
Please find attached the graph of it.
Answer:
7/12 cannot be reduced
Step-by-step explanation:
7 = 7
12 = 2 * 2 * 3
7 and 12 have no common factors other than 1, so the fraction 7/12 cannot be reduced. 7/12 is already written in lowest terms.
Answer:
7.635
Step-by-step explanation:
i hope it helps:)