4 years ago

How do you solve 3=-4p+3

Mathematics

2 answers:

ivanzaharov [21]4 years ago

7 0

3 = -4p + 3 3 - 3 = -4p 0 = -4p 0/-4 = p P = 0

Oksi-84 [34.3K]4 years ago

3 0

4 × 0 = 0 3 + 0 = 3

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Use the remainder theorem to determine the remainder when 3t²+5t-7 is divided by t-5

Brrunno [24]

$f(t)=3t^2+5t-7\implies f(5)=3(5)^2+5(5)-7=93$

which means the remainder upon dividing $f(t)$ by $t-5$ is 93.

This is because we can write

$\dfrac{f(t)}{t-5}=q(t)+\dfrac{r(t)}{t-5}$

where $q(t)$ is the quotient and $r(t)$ is the remainder. Multiplying both sides by $t-5$ , then evaluating at $t=5$ makes the $q(t)$ term vanish, leaving the remainder:

$f(t)=q(t)(t-5)+r(t)\implies f(5)=r(5)$