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puteri [66]
2 years ago
7

2 1/3⋅3 1/2 i need to KNOW NOW!!!!

Mathematics
1 answer:
Sveta_85 [38]2 years ago
4 0

Answer:

fraction form: 49/6

decimal from: 8.16

mixed form: 8 1/6

Step-by-step explanation:

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Don’t answer the question
mixer [17]
Answer is 72566.52

77000-5203=71797

3840-571=3269

71797+3269=75066

75066-2500=72566

72566+0.52=72566
8 0
3 years ago
Read 2 more answers
4. What is the correct ratio for sin A?<br> A) 5/12<br> B) 12/13<br> C) 5/13<br> D) 13/12
maxonik [38]

Answer:

sin A = 12 /13

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin A = opp / hyp

sin A = 12 /13

5 0
2 years ago
What is the value of x when 9x=45
kkurt [141]

Answer:

5

Step-by-step explanation:

45 divided by 9= 5

6 0
3 years ago
Read 2 more answers
Find the gradient of the line <br><br> 3y + 2x = 1<br><br> how to guys
kykrilka [37]

Answer:

-2/3

Step-by-step explanation:

The gradient of a line is its slope. You can just convert the equation to slope-intercept form (y=mx+b where "m" is the gradient/slope):

3y + 2x = 1

3y = 1 - 2x

y = 1/3 - 2/3x

y = -2/3x + 1/3

So, as we can see, -2/3 is the gradient/slope of the line.

5 0
2 years ago
The weights of 67 randomly selected axles were found to have a variance of 3.85. Construct the 80% confidence interval for the p
VLD [36.1K]

Answer:

3.13

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 67

Variance = 3.85

We have to find 80% confidence interval for the population variance of the weights.

Degree of freedom = 67 - 1 = 66

Level of significance = 0.2

Chi square critical value for lower tail =

\chi^2_{1-\frac{\alpha}{2}}= 51.770

Chi square critical value for upper tail =

\chi^2_{\frac{\alpha}{2}}= 81.085

80% confidence interval:

\dfrac{(n-1)S^2}{\chi^2_{\frac{\alpha}{2}}} < \sigma^2 < \dfrac{(n-1)S^2}{\chi^2_{1-\frac{\alpha}{2}}}

Putting values, we get,

=\dfrac{(67-1)3.85}{81.085} < \sigma^2 < \dfrac{(67-1)3.85}{51.770}\\\\=3.13

Thus, (3.13,4.91) is the required 80% confidence interval for the population variance of the weights.

8 0
3 years ago
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