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2 years ago

Please help me with 23 three

Mathematics

1 answer:

MrRissso [65]2 years ago

6 0

Look at the back for answers ( my workbook has answers)

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Graph ∆KLM with vertices K(2,2), L(0,- 1), and M(-3,2). Graph ∆K'L'M' with a scale factor of 2. What are the coordinates of the

olasank [31]

Answer:

The coordinates of the new vertices are:

K'(4,4), L'(0,- 2), and M'(-6,4).

Step-by-step explanation:

In order to dilate a shape by 2, you can simply multiply the coordinates of the orignal triangle each by 2 to find the new coordinates of the new vertices.

K(2,2), L(0,- 1), and M(-3,2)

K'(2*2,2*2), L'(0*2,- 1*2), and M'(-3*2,2*2).

Now become...

K'(4,4), L'(0,- 2), and M'(-6,4).

You can now graph ∆K'L'M' using these coordinates.

5 0

2 years ago

What are the coordinates of point B on \overline{AC} such that AB = 1/2 BC

marta [7]

Answer:

C. $B(x,y) = \left(3,-\frac{16}{3} \right)$

Step-by-step explanation:

Let $A(x,y) = (6,-7)$ , $B(x,y) = (x,y)$ and $C(x,y) = (-3,-2)$ . From statement we know that $AB = \frac{1}{2}\cdot BC$ , which is equivalent to the following linear algebraic formula:

$B(x,y) -A(x,y) = \frac{1}{2}\cdot [C(x,y)-B(x,y)]$ (1)

$B(x,y)-A(x,y) = \frac{1}{2}\cdot C(x,y)-\frac{1}{2}\cdot B(x,y)$

$\frac{3}{2}\cdot B(x,y) = \frac{1}{2}\cdot C(x,y)+A(x,y)$

$B(x,y) = \frac{1}{3}\cdot C(x,y) +\frac{2}{3}\cdot A(x,y)$ (2)

Then, the coordinates of point B on AC are:

$B(x,y) = \frac{1}{3}\cdot (-3,-2)+\frac{2}{3}\cdot (6,-7)$

$B(x,y) = \left(-1, -\frac{2}{3}\right)+\left(4, -\frac{14}{3} \right)$

$B(x,y) = \left(3,-\frac{16}{3} \right)$

Which means that correct answer is C.

5 0

2 years ago

Find the distance between the line 1.2x − 0.5y + 1.1=0 and the origin.

denpristay [2]

Answer:

The answer to your question is: d = 0.85 units

Step-by-step explanation:

Data

Line equation: 1.2 x − 0.5 y + 1.1 = 0 A = 1.2; B = -0.5; C = 1.1

Point (0, 0) x = 0; y = 0

Formula

d = | Ax + By + C | / √(A² + B²)

Process

d = |(1.2)(0) + (-0.5)(0) + 1.1 | / √ (1.2)² + (0.5)²

d = | 1.1 | / √ 1.44 + 0.25

d = 1.1 / √ 1.69

d = 1.1 / 1.3

d = 0.85 units

7 0

2 years ago

Judd worked 40 hours this week. He worked 7/10 of the hours outside and the rest inside. How many hours did he work outside?

Mnenie [13.5K]

If you would like to know how many hours did Judd work outside, you can calculate this using the following steps:

40 hours
outside: 7/10 of the hours = 7/10 * 40 hours = 7/10 * 40 = 28 hours

Judd worked 28 hours outside.

3 0

3 years ago

Freeeeeeeeeeeeeeeeee again

Paraphin [41]

Answer:

cool

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers