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dimulka [17.4K]
3 years ago
10

Suppose you throw a ball upward, with an initial velocity of 50 feet per second, from the roof of a 160-foot-high building.

Mathematics
1 answer:
MrRa [10]3 years ago
4 0

Answer:

letter a po Ang sagot diyan

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6=1-2n+5 how do I solve this?
Ivanshal [37]
6=1-2n+5\\ \\2n=1+5-6\\ \\ 2n=0\ \ /:2\\ \\ n=0
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3 years ago
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Solve the equation 0.3x-2=0.1(x+20) whats the solution set?
Inga [223]

x = 40/2 = 20 i think thsts the answer if I was wrong you have to right to slap my face

7 0
3 years ago
Please help!!
erastova [34]

Answer:

  180, 180, 148, 180, 148

Step-by-step explanation:

The two rules in play here are ...

  • the sum of interior angles of a triangle is 180°
  • the angles of a linear pair are supplementary (they total 180°)

__

The first of these rules answers the first two questions:

  • interior angles total 180°
  • angles 1, 3, 4 total 180°

We can subtract the measure of angle 1 from both sides of the previous equation to find the sum of the remaining two angles.

  • angles 3 and 4 total 148°

The second rule answers the next question:

  • angles 1 and 2 total 180°

As before, subtracting the value of angle 1 from both sides of the equation gives ...

  • angle 2 must be 148°

_____

<em>Additional comment</em>

Of course, the subtraction property of equality comes into play, also. For some unknown, X, you have (in both cases) ...

  X + 32° = 180°

  X +32° -32° = 180° -32° . . . . . . subtraction property of equality

  X = 148° . . . . . . . . simplify

In the first case, X is the sum of angles 3 and 4. In the second case, X is angle 2 only.

7 0
3 years ago
Pls help me with this question.
maw [93]

Answer:

The slope for this equation is \frac{1}{7}.

Step-by-step explanation:

                       x         y

point 1:           -4        -3

point 2:           3        -2  

slope:             \frac{1}{7}

To solve for slope here is an equation, to help: \frac{y^2-y^1}{x^2-x^1}

\frac{y^2-y^1}{x^2-x^1} \\\\\frac{-2-(-3)}{3-(-4)} \\\\= \frac{1}{7} \\

5 0
3 years ago
Calculate the axis of symmetry in the equation Y = (x+1) (x-4)
algol [13]

Answer:

<em>Every </em><em>parabola </em><em>has </em><em>a </em><em>turning</em><em> point</em><em> </em><em>called </em><em>the </em><em>axis</em><em> of</em><em> symmetry</em><em>,</em><em>so </em><em>for </em><em>this </em><em>question</em><em> </em><em>you </em><em>just</em><em> </em><em>have </em><em>to </em><em>find </em><em>the </em><em>turning</em><em> </em><em>points</em>

<em>x </em><em>turning</em><em> </em><em>point</em><em>=</em><em> </em><em>-b/</em><em>2</em><em>a</em><em>,</em><em>and </em><em>the </em><em>y </em><em>turning</em><em> </em><em>point</em><em> </em><em>is </em><em>gotten</em><em> </em><em>by </em><em>replacing</em><em> </em><em>the </em><em>value </em><em>of </em><em>x </em><em>in </em><em>the </em><em>equation</em>

<em>y=</em><em>(</em><em>x+</em><em>1</em><em>)</em><em>(</em><em>x-4)</em>

<em> </em><em> </em><em>=</em><em>x^</em><em>2</em><em>-</em><em>3</em><em>x</em><em>-</em><em>4</em>

<em>a </em><em>is </em><em>1</em><em>,</em><em>b </em><em>is </em><em>-</em><em>3</em><em> </em><em>and </em><em>c </em><em>is </em><em>-</em><em>4</em>

<em>x=</em><em> </em><em>-</em><em>(</em><em>-</em><em>3</em><em>)</em><em>/</em><em>2</em><em>(</em><em>1</em><em>)</em>

<em> </em><em> </em><em>=</em><em>1</em><em>.</em><em>5</em>

<em>and </em><em>y=</em><em>x^</em><em>2</em><em>-</em><em>3</em><em>x</em><em>-</em><em>4</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>1</em><em>.</em><em>5</em><em>^</em><em>2</em><em>-</em><em>3</em><em>(</em><em>1</em><em>.</em><em>5</em><em>)</em><em>-</em><em>4</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>-</em><em>6</em><em>.</em><em>2</em><em>5</em>

<em>therefore</em><em> </em><em>the </em><em>axis </em><em>of</em><em> symmetry</em><em> is</em><em> (</em><em>1</em><em>.</em><em>5</em><em>,</em><em>-</em><em>6</em><em>.</em><em>2</em><em>5</em><em>)</em>

<em>I </em><em>hope </em><em>this </em><em>helps</em>

6 0
3 years ago
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