Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
If you look carefully at the graph, you may see that the slope of the line is
3-4 -1
---------------- = ------ = m
7-4 3
thus, you have the slope of the line and two points on the line. Suppose we
choose the point (4,4) and subst. the known slope and the coordinates of this point into the point-slope formula for the eqn of a str line:
y-y1 = m (x-x1)
y-4 = (-1/3)(x-4)
This is the desired equation. You could, if you wished, change this into slope-intercept form.
Step-by-step explanation:
y = ¼x + 2
m1 = ¼
m of line perpendicular = m2
the formula is : m1×m2 = -1
=> m2 = -1 ÷ m1
= -1 ÷ ¼ = -4
so, the equation is :
y = -4x - 7 (option A)
Answer:
21/42
Step-by-step explanation:
Hope this helps :)
