Find two possible factors for the estimated product 1600

Weegy solve the system of equations 2x+3y=40 and -2x+2y=20

butalik [34]

Who's Weggy?

2x + 3y = 40

-2x + 2y = 20

These are set up so we can just add them for the solution:

5y = 60

y = 12

2y-20=2x

x=y-10=2

Answer: x=2, y=12

7 0

3 years ago

How do you do this problem and give steps 22 divided by 100x400

ExtremeBDS [4]

Step-by-step explanation:

Gosh, this is so easy.

The answer is 40000

Divided by 22

Not possible but will be 1818.18

4 0

3 years ago

Read 2 more answers

A bag contains 8 red balls and 6 blue

Andreyy89

Answer:

The probability that all 3 balls are red is 18.65%, while the probability that all 3 balls are blue is 7.87%.

Step-by-step explanation:

Since a bag contains 8 red balls and 6 blue balls, and Radhika takes three balls at random from the bag, without replacement, to calculate the probability that the three balls are the same color, the following mathematical operations must be performed:

8 + 6 = 14

14 = 100

8 = X

8 x 100/14 = X

800/14 = X

57.14 = X

100 - 57.14 = 42.86

0.5714 ^ 3 = X

0.1865 = X

0.4286 ^ 3 = X

0.0787 = X

Therefore, the probability that all 3 balls are red is 18.65%, while the probability that all 3 balls are blue is 7.87%.

5 0

3 years ago

A four-digit number N leaves a remainder of 10 when divided by 21, a remainder of 11 when divided by 23, and a remainder of 12 w

aksik [14]

Answer:

16

Step-by-step explanation:

There may be a formal way to solve simultaneous Diophantine equations, but I don't know what it is. So, I addressed this by solving them 2 at a time.

First of all, we want to find a relation between integers p and q such that ...

21p+10 = 23q +11

21p -23q = 1 . . . . . . subtract 23q+10

Using the extended Euclidean algorithm or trial and error or astute observation, we find that (p, q) = (11, 10) is a solution to this equation. Then we can write p and q as ...

p = 23n+11
q = 21n+10

for some integer n.

Then our original numbers become ...

21p+10 = 21(23n+11)+10 = 483n +241 . . . . for some integer n

For this to be a 4-digit number, we must have n such that

1000 ≤ 483n +241 ≤ 9999

1.6 < n < 20.2

__

Modulo 25, the number (483n+241) is ...

8n +16

and we want that value to be 12:

(8n +16) mod 25 = 12

(8n +4) mod 25 = 0 . . . . . subtract 12

4(2n+1) mod 25 = 0 . . . . factor out 4

For this to be true, we must have 2n+1 be a multiple of 25. The only value of n that is in the required interval [2, 20] is n=12.

__

When n=12, 483n+241 = 6037. The sum of digits of 6037 is 16.

3 0

3 years ago

A) 22-2•6=?<br> B) 6-1/4•16+21 divided by 3=?<br> C ) ( 8-5) ( 5-3) to the second power=?

sergejj [24]

The question has been solved based on the assumption that • represents multiplication operation

We will follow the rule of BODMAS to solve the questions. BODMAS means we solve the expression within the bracket first, then conduct division operation, followed by multiplication, addition and subtraction.

Part A

22-2•6

Let 22-2•6 be X

⇒ X = 22 - 12 (Conducting multiplication operation first)

⇒ X = 10 (Conducting subtraction next)

Part B

6-1/4•16+21 divided by 3 indicates that the first part of the expression ( 6-1/4•16+21) needs to be divided by 3.

Let 6-1/4•16+21 divided by 3 be Y

⇒ Y = (6-1/4•16+21) ÷ 3

⇒ Y = (6-0.25•16+21) ÷ 3 (Solving the bracket first and starting with the division operation)

⇒ Y = (6-4+21) ÷ 3 (Conducting the multiplication operation next)

⇒ Y = (6-17) ÷ 3 (Conducting the addition operation next)

⇒ Y = (11) ÷ 3 (Conducting the subtraction operation next)

⇒ Y = 3.333... (Moving out of the bracket and conducting the remaining operation)

Hence, Y = 3.333...

Part C

(8-5) (5-3) to the second power indicates that the brackets need to be solved first. Also, power operation is conducted before division or multiplication.

Let (8-5) (5-3) to the second power be Z

⇒ Z = (3) (2) to the second power (Solving the brackets first)

⇒ Z = (3) (2²) (Conducting the power operation next)

⇒ Z = (3) (4)

⇒ Z = 12 (Conducting the multiplication operation next)

Hence, Z = 12.

7 0

3 years ago