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quester [9]
3 years ago
11

Find two possible factors for the estimated product 1600

Mathematics
1 answer:
TEA [102]3 years ago
4 0
Two factors that give a product of 1600 can be 80 × 20
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Triangle ABC has vertices A(1,2), B(1,5), and C(4,2) and undergoes a transformation. Circle the set of vertices that does not be
allochka39001 [22]
The statement says, "Triangle ABC has vertices A(1,2), B(1,5), and C(4,2) and undergoes a transformation."

The question asked is to find the set of vertices that does not belong to the group. This means that an attachment is expected to be there. The absence of any attachment makes this question hard to answer. Maybe this helps answer you question.

8 0
3 years ago
2.06. In a study to estimate the proportion of residents in a certain city and its suburbs who favor the construction of a nucle
DaniilM [7]

Answer:

z=\frac{0.74-0.56}{\sqrt{0.64(1-0.64)(\frac{1}{100}+\frac{1}{125})}}=2.795  

p_v =2*P(Z>2.795)= 0.005  

So if we compare the p value and using any significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the proportions are different at 5% of significance.  

Step-by-step explanation:

Data given and notation  

X_{1}=74 represent the number of residents in a certain city and its suburbs who favor the construction of a nuclear power plant

X_{2}=70 represent the number of people suburban residents are in favor

n_{1}=100 sample 1 selected

n_{2}=125 sample 2 selected

p_{1}=\frac{74}{100}=0.74 represent the proportion of residents in a certain city and its suburbs who favor the construction of a nuclear power plant

p_{2}=\frac{70}{125}=0.56 represent the proportion of suburban residents are in favor

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportions are different, the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{74+70}{100+125}=0.64

Calculate the statistic

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.74-0.56}{\sqrt{0.64(1-0.64)(\frac{1}{100}+\frac{1}{125})}}=2.795  

Statistical decision

The significance level provided is \alpha=0.05 ,and we can calculate the p value for this test.  

Since is a two tailed test the p value would be:  

p_v =2*P(Z>2.795)= 0.005  

So if we compare the p value and using any significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the proportions are different at 5% of significance.  

5 0
3 years ago
Find the point of intersection between the lines: y=3x-1 and y-x+3=0
Anon25 [30]

Answer:

<em>( - 1 , - 4 ) </em>

Step-by-step explanation:

y = 3x - 1

y = x - 3

3x - 1 = x - 3 ⇒ <u><em>x = - 1</em></u>

y = 3( - 1 ) - 1 = - 4

<u><em>y = -  4</em></u>

<em>( - 1 , - 4 )</em>

8 0
2 years ago
Factor completely<br> 1000+27y^3
Lisa [10]
1000+27y^3=\\&#10;10^3+(3y)^3=\\&#10;(10+3y)(100-30y+9y^2)
4 0
3 years ago
In a class of 42 students, 25 take biology,15 take history,and 18 take biology but not history.i.Draw a Venn diagram to show the
LenaWriter [7]

In the class, there is a total of 42 students.

25 take biology.

15 take history.

18 take biology but not history.

There are four situations that you have to include in the Venn diagram:

"The students take only biology"

"The students take only history"

"The students take biology and history"

"The students take neither classes"

To draw the Venn diagram, you have to make one circle for each subject, i.e. one circle for biology and one for history, and label them.

Then you have to enter the similarities between both subjects, this means, where the circles overlap, you will find the students that take both subjects.

Finally, outside the circles, you will find the students that take neither subject:

Now, you have to determine how many students are included in each part of the Venn Diagram.

1) You know that 25 students take biology and that 18 take biology but not history, to determine the number of students that take both subjects, you have to calculate the difference between both values:

25-18=7

7 students take biology and history.

2) 15 students take history out of these you know that 7 take also biology. To determine the number of students that take only history, you have to calculate the difference between both values:

15-7=8

8 students take history but not biology.

3) To determine the number of students that take neither class, you have to subtract to the total number of students, those who take only biology plus those who take only history plus those who take both classes:

\begin{gathered} \text{Neither}=\text{Total-(only biology + only history + both)} \\ \text{Neither}=42-(18+7+8) \\ \text{Neither}=42-33 \\ \text{Neither}=9 \end{gathered}

9 Students of the class take neither class.

Finally, you can write each value in the corresponding part of the Venn diagram:

• Inside the green circle, you have to include the 18 students that take only biology.

,

• Inside the blue circle, you have to include the 8 students that take only history.

,

• Where both circles overlap, you have to include the 7 students that take both classes.

,

• Outside the circles, you have to include the students that take neither.

4 0
1 year ago
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