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Klio2033 [76]
4 years ago
12

The measure of angle QPR = ??? degrees

Mathematics
1 answer:
Ostrovityanka [42]4 years ago
3 0
The measure of angle QPR is 30 degrees
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Totally blanking on how medians work
Elis [28]
<h3>Answer: FC = 16</h3>

===============================================

The three medians of this triangle are:

  • PF
  • RE
  • QD

These segments go from one vertex to the midpoint of the opposite side.

The median we'll focus on is PF.

The point C is the centroid of the triangle. It's where the three medians intersect. It turns out that C divides PF such that CF is twice as long as PC

In other words,

CF = 2*PC

This means,

PF = PC+CF .... segment addition postulate

PF = PC+2*PC ... replace CF with 2*PC

PF = 3*PC .... combine like terms

So the median PF is three times the length of its portion PC

We're told that PF = 24

We can then find the following:

PF = 3*PC

24 = 3*PC

3*PC = 24

PC = 24/3

PC = 8

Then we double this to get the length of CF

CF = 2*PC

CF = 2*8

CF = 16

This is the same as FC because the order of the endpoints don't matter when it comes to naming a segment.

The final answer is 16.

5 0
3 years ago
Please help thank you
Leona [35]

Answer:

x=35

Step-by-step explanation:

3x+15=2x+50 (opposite angles are equal)

3x=2x+35

x=35

4 0
3 years ago
Plz plz help test due soon
Dvinal [7]

Answer:

22

Step-by-step explanation:

8 0
4 years ago
Helppp ill give you brainliest ​
Ymorist [56]

Answer:

A!

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help!! i have no clue what to do and this packet is due tonight.
Stels [109]

Answer:

[D] ∞

General Formulas and Concepts:

<u>Calculus</u>

Limits

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle  \lim_{n \to \infty} s(n)<em />

<em />\displaystyle s(n) = (\frac{5}{4n^4})(3n^5 + 3n^4 + 2n^3 + n^2)<em />

<em />

<u>Step 2: Evaluate</u>

  1. Substitute in function [Limit]:                                                                           \displaystyle  \lim_{n \to \infty} (\frac{5}{4n^4})(3n^5 + 3n^4 + 2n^3 + n^2)
  2. Multiply:                                                                                                             \displaystyle  \lim_{n \to \infty} \frac{5(3n^5 + 3n^4 + 2n^3 + n^2)}{4n^4}
  3. Power Method:                                                                                                 \displaystyle  \lim_{n \to \infty} \frac{5(3n^5 + 3n^4 + 2n^3 + n^2)}{4n^4} = \infty

Since the degree of the polynomial is greater in the numerator than in the denominator, the top will always increase faster than the bottom, thus getting infinitely larger.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Book: College Calculus 10e

7 0
4 years ago
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