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3 years ago

What is the truth value for the following conditional statement?

Mathematics

1 answer:

blsea [12.9K]3 years ago

5 0

Answer:

its T or the 3rd one

Step-by-step explanation:

i guessed

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What is the measurement of F?

Norma-Jean [14]

44 degrees is the answer

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3 years ago

Practice with Conversions

mylen [45]

Answer:

1) Newbury Park → The distance is accurate.

2) Thousand Oaks → The distance is not accurate.

3) Los Angeles → The distance is not accurate.

Step-by-step explanation:

It is important to remember that:

$1\ mile=1.609\ kilometers$

Knowing this, you can make the corresponding conversions:

1) Newbury Park

10 miles to kilometers:

$(10\ mi)(\frac{1.609\ km}{1\ mi})=16.0\ km$

The distance shown in that California highway sign is accurate.

2) Thousand Oaks

13 miles to kilometers:

$(13\ mi)(\frac{1.609\ km}{1\ mi})=20.9\ km$

The distance shown in that California highway sign is not accurate.

3) Los Angeles

55 miles to kilometers:

$(55\ mi)(\frac{1.609\ km}{1\ mi})=88.4\ km$

The distance shown in that California highway sign is not accurate.

3 0

3 years ago

“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor

Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

$C=2\pi r$

Find the radius of the sphere with a 5.50-meter circumference

For $C=5.50\ m$

assume

$\pi =3.14$

substitute and solve for r

$5.50=2(3.14)r$

$r=5.50/[2(3.14)]=0.88\ m$

Find the radius of the sphere with a 7.85-meter circumference

For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

Find the surface area of sphere with a 5.50-meter circumference

For $r=0.88\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(0.88)^{2}$

$SA=9.73\ m^{2}$

Find the surface area of sphere with a 7.85-meter circumference

For $r=1.25\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

Find the cost of sphere with a 5.50-meter circumference

$9.73*(92)=\$895.16$

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Find the cost of sphere with a 7.85-meter circumference

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0

3 years ago

2x+20=-3x-25 help me solve it

zysi [14]

The correct answer is x= -9. Hope this helps!!

8 0

3 years ago

Read 2 more answers

What is the constant of proportionality between y and x in the graph

VMariaS [17]

Answer:

y/x =2/3

Step-by-step explanation:

you just need see at one point. for example: (3, 2)

4 0

3 years ago