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grin007 [14]
3 years ago
5

11j-20=6j+15 please help

Mathematics
1 answer:
Ronch [10]3 years ago
6 0

Answer:

j=7

Step-by-step explanation:

11j-20=6j+15

-6j          -6j  

5j-20=15  Isolate the variable:

  +20  +20

5j=35 Divide to get variable by itself

j=7  

Hope this helps :)

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(2x-7)-(4x^2+6x-3)+(x^2+4)
masha68 [24]

Answer:

-3x^2-4x

Step-by-step explanation:

Simplify:

\left(2x-7\right)-\left(4x^2+6x-3\right)+\left(x^2+4\right)

=2x-7-\left(4x^2+6x-3\right)+x^2+4

Group same factor:

=-\left(4x^2+6x-3\right)+x^2+2x-7+4

Add :

=-\left(4x^2+6x-3\right)+x^2+2x-3

Apply the distributive law: -(a+b) = -a - b

-\left(4x^2+6x-3\right)=-4x^2-6x+3

=-4x^2-6x+3+x^2+2x-3

Group same factor:

=-4x^2+x^2-6x+2x+3-3

Subtract:

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<u><em>~lenvy~</em></u>

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