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grin007 [14]
3 years ago
5

11j-20=6j+15 please help

Mathematics
1 answer:
Ronch [10]3 years ago
6 0

Answer:

j=7

Step-by-step explanation:

11j-20=6j+15

-6j          -6j  

5j-20=15  Isolate the variable:

  +20  +20

5j=35 Divide to get variable by itself

j=7  

Hope this helps :)

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Is 10(x-2)=5(2x-4) infinitely many or no solution
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4 years ago
2,000,000 mg = how many kg?
cluponka [151]
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3 years ago
Please please help help please please ASAP
krek1111 [17]

Answer:

false

Step-by-step explanation:

The horizontal axis is the x axis.

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7 0
3 years ago
A thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F. Af
fgiga [73]

Answer:

53.3324

Step-by-step explanation:

given that a  thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F.

By Newton law of cooling we have

T(t) = T+(T_0-T)e^{-kt}

where T (t) is temperature at time t,T =surrounding temperature = 40, T0 =70 = initial temperature

After half minute thermometer reads 60° F. Using this we can find k

T(0,5) = 40+(70-40)e^{-k/2} = 60\\e^{-k/2} =2/3\\-k/2 = -0.4055\\k = 0.8110

So equation is

T(t) = 40+(30)e^{-0.8110t}\\

When t=1,

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T(1) = 40+(30)e^{-0.8110}\\\\=53.3324

5 0
3 years ago
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